public String display(){ String data = "\n商品名称:"+componname+ "\n商品品牌:"+brand+ "\n电话:"+tel+ "\n地址:"+address+ "\n价格:"+price+ "\n数量:"+number+ "\n状态:"; if (state == 1) data = data + "未支付"; if (state == 2) data = data + "待发货"; if (state == 3) data = data + "已发货"; data = data + "\n创建时间:"+createtime; if (paytime != null) data = data + "\n付款时间:"+ paytime; return data; }
时间: 2024-02-14 09:22:31 浏览: 16
这段代码看起来像是一个Java类中的一个方法,它会返回一个包含商品信息的字符串。其中,商品信息包括商品名称、品牌、电话、地址、价格、数量、状态、创建时间和付款时间(如果存在)。状态字段会根据不同的值显示不同的文本。如果状态为1,显示“未支付”,如果状态为2,显示“待发货”,如果状态为3,显示“已发货”。这个方法的作用可能是将商品信息格式化为字符串,以便在系统中进行展示或者输出。
相关问题
用java实现s=n+nn+nnn+……
以下是 Java 代码实现 s=n+nn+nnn+……:
```java
import java.util.Scanner;
public class ConcatenateNumber {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
System.out.println("请输入一个整数 n:");
int n = scanner.nextInt();
System.out.println("请输入一个整数 m:");
int m = scanner.nextInt();
int s = 0;
int t = 0;
for (int i = 1; i <= m; i++) {
t = t * 10 + n;
s += t;
}
System.out.println("s = " + s);
}
}
```
运行程序后,首先输入一个整数 n,然后输入一个整数 m,程序会自动计算出 s = n + nn + nnn + …… 的值,输出结果。例如,当输入 n=3,m=4 时,程序输出:
```
请输入一个整数 n:
3
请输入一个整数 m:
4
s = 3702
```
其中,3702 = 3 + 33 + 333 + 3333。
public class Test{ public static void main(String[] args){ String s1 = "runoob"; String s2 = "runoob"; System.out.println("s1 == s2 is:" + s1 == s2);}}
The code you provided has a small mistake in the print statement. The expression `"s1 == s2 is:" + s1` is concatenated with `== s2` before being passed to `System.out.println()`. This causes a compilation error because you cannot concatenate a string with a boolean value directly.
To fix this, you need to use parentheses to group the concatenation expression properly. Here's the corrected code:
```java
public class Test {
public static void main(String[] args) {
String s1 = "runoob";
String s2 = "runoob";
System.out.println("s1 == s2 is: " + (s1 == s2));
}
}
```
In this corrected code, the expression `(s1 == s2)` is properly grouped and then concatenated with the string `"s1 == s2 is: "`.