print(list(map(lambda a: a*3,num)))
时间: 2024-03-04 09:54:00 浏览: 23
这行代码使用了 `map` 函数和 `lambda` 表达式,将列表 `num` 中的每个元素都乘以 3,并将结果作为一个新的列表输出。
具体来说,`map` 函数将一个 lambda 函数应用到列表 `num` 中的每个元素上,并将结果作为一个新的迭代器返回。其中,lambda 函数的定义为 `lambda a: a * 3`,表示以一个参数 `a` 为输入,将其乘以 3 后返回结果。然后将迭代器转换为列表并输出结果。
例如,列表 `num` 中的第一个元素为 10,将其作为参数传递给 lambda 函数后,得到的结果为 30。同样地,对于 `num` 中的其他元素也会进行类似的计算,并返回一个包含计算结果的列表。最终输出结果为 `[30, 60, 120, 240, 480]`。
相关问题
for num in range(100,1000): r=map(lambda x:int(x)**3,str(num)) if sum(r)==num: print(num)
As an AI language model, I cannot execute code, but I can explain what this code does.
This code is checking for all three-digit numbers that are equal to the sum of the cubes of their digits.
The code first iterates through all numbers from 100 to 999 using the `range()` function.
For each number, it converts it to a string and then maps the `int()` function to each digit in the string to convert it to an integer. It then cubes each integer using the `**` operator and returns the list of cubes.
The `sum()` function is then used to add up all the cubes, and if the sum equals the original number, it is printed to the console.
This code is an example of a brute-force approach to solving a problem, as it simply checks every possible three-digit number until it finds the ones that meet the criteria.
for num in range(100,1000): r=map(lambda x:int(x)**3,str(num))
if sum(r)==num: print(num)
This code finds all the Armstrong numbers between 100 and 999. An Armstrong number is a number that is equal to the sum of its own digits raised to the power of the number of digits. For example, 153 is an Armstrong number because 1^3 + 5^3 + 3^3 = 153.
The code uses a for loop to iterate through all the numbers between 100 and 999. It then converts each number to a string and applies a lambda function to each digit to raise it to the power of 3. The resulting list of cubed digits is then summed up and checked against the original number. If they are equal, the number is printed out as an Armstrong number.
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