public class Add : Calculation { //构造函数 public Add(double num1, double num2) : base(num1, num2) { } //重写父类中的抽象方法 public override double YunSuan() { return this.DouNum1 + this.DouNum2; } }
时间: 2023-06-14 14:03:28 浏览: 45
这是一个继承自 Calculation 类的 Add 类,它实现了 Calculation 中的抽象方法 YunSuan(),并且在其中实现了加法运算。构造函数接收两个 double 类型的参数并传递给父类的构造函数。通过继承 Calculation 类,Add 类可以使用 Calculation 类中的属性和方法,同时也可以重写 Calculation 类中的抽象方法。
相关问题
head_dim = dim // num_heads
As an AI language model, I can understand that this line of code is used to calculate the dimension of each head in multi-head attention.
Here, `dim` refers to the input dimension of a sequence, and `num_heads` refers to the number of attention heads.
The variable `head_dim` is assigned the value of `dim` divided by `num_heads`. This calculation results in the size of each head in the multi-head attention mechanism.
For example, if `dim` is 512 and `num_heads` is 8, then `head_dim` would be 64. This means that the input sequence will be divided into 8 different parts or heads, each with a dimension of 64.
cout << (c << 1) - (t * t == num)
This code snippet uses bitwise left shift operator (<<) to shift the value of variable c by 1 bit to the left, effectively multiplying it by 2. The result is then subtracted from a boolean expression (t * t == num) which evaluates to 1 or 0 depending on whether the square of variable t is equal to num.
The purpose of this code snippet is unclear without additional context, but it seems to be related to some calculation involving variables c, t, and num. The boolean expression may be used to conditionally adjust the result of the left shift operation.