idea中raw use of parameterized class警告如何解决
时间: 2023-03-26 13:02:03 浏览: 681
这个警告通常是由于使用泛型时没有指定具体类型而导致的,可以通过指定具体类型或者使用 @SuppressWarnings("rawtypes") 注解来解决。具体方法可以参考 IDEA 官方文档或者搜索相关资料。
相关问题
Raw use of parameterized class
The raw use of a parameterized class refers to using the class without specifying the type parameter. In languages like Java or C#, parameterized classes allow you to create classes that can work with different types. However, if you use the class without specifying the type parameter, it is considered a raw use.
For example, let's say we have a generic class called `Box` that can hold any type of object:
```java
public class Box<T> {
private T value;
public void setValue(T value) {
this.value = value;
}
public T getValue() {
return value;
}
}
```
If we use this class without specifying the type parameter, it becomes a raw use:
```java
Box box = new Box(); // Raw use of Box
box.setValue("Hello"); // No type safety
String value = (String) box.getValue(); // Type casting required
```
In the above example, `Box box = new Box();` is a raw use because we are not specifying the type parameter. This results in the loss of type safety, as we can assign any type of value to the `value` field without any compiler checks. We also need to perform explicit type casting when retrieving the value.
It is generally recommended to avoid raw uses of parameterized classes as they bypass the type safety provided by generics and can lead to runtime errors or unexpected behavior.
Raw use of parameterized class 'ArrayList'警告如何消除
消除Raw use of parameterized class 'ArrayList'警告的方法是使用泛型,即在声明ArrayList时指定其类型参数。例如,使用ArrayList<String>代替ArrayList即可消除警告。如果你需要在列表中存储多种类型的对象,可以使用ArrayList<Object>。另外,如果你确定列表中只包含一种类型的对象,可以使用特定的类作为类型参数,例如ArrayList<Integer>或ArrayList<Person>。