C语言去掉一个最高分一个最低分求最终成绩

假设有n个成绩，我们可以先将它们从小到大排序，然后去掉最低分和最高分，再将剩下的n-2个成绩求平均值即可得到最终成绩。具体的C语言代码如下：

#include <stdio.h>
#include <stdlib.h>

int cmp(const void *a, const void *b) {
    return *(int *)a - *(int *)b;
}

int main() {
    int n;
    printf("请输入成绩个数：");
    scanf("%d", &n);
    int *scores = (int *)malloc(n * sizeof(int));
    printf("请输入%d个成绩：", n);
    for (int i = 0; i < n; i++) {
        scanf("%d", &scores[i]);
    }
    qsort(scores, n, sizeof(int), cmp);
    int sum = 0;
    for (int i = 1; i < n - 1; i++) {
        sum += scores[i];
    }
    printf("最终成绩为：%d\n", sum / (n - 2));
    free(scores);
    return 0;
}

相关问题

c语言使用函数去掉一个最高分和最低分求平均分

可以使用以下的 C 语言代码实现该功能：

#include <stdio.h>

float avgWithoutMinMax(float arr[], int n) {
    float sum = 0.0;
    float min = arr[0], max = arr[0];

    // 找出最大值和最小值
    for (int i = 0; i < n; i++) {
        if (arr[i] < min) {
            min = arr[i];
        }
        if (arr[i] > max) {
            max = arr[i];
        }
        sum += arr[i];
    }

    // 减去最大值和最小值
    sum = sum - min - max;

    // 计算平均值
    return sum / (n - 2);
}

int main() {
    float scores[] = { 80.5, 90.0, 75.5, 85.0, 95.0 };
    int n = sizeof(scores) / sizeof(scores[0]);

    float avg = avgWithoutMinMax(scores, n);
    printf("平均分是: %.2f", avg);

    return 0;
}

该程序使用了一个 `avgWithoutMinMax` 函数来计算去掉最高分和最低分后的平均值。首先，它遍历一遍数组来找出最大值和最小值，并累加所有分数的和。然后，它减去最大值和最小值，最后计算平均值并返回。在 `main` 函数中，我们定义了一个数组 `scores` 来存储成绩，并使用 `sizeof` 函数来计算数组的长度。最后，我们调用 `avgWithoutMinMax` 函数来计算平均分，并使用 `printf` 函数输出结果。

用c语言写一个五个评委为参赛选手打分，选手最后得分要去掉一个最高分，去掉一个最低分，然后求平均分作为选手成绩。不用数组

您好！感谢您使用 ChitGPT 进行对话。根据您的需求，我可以提供以下 C 语言代码，实现对五个评委为参赛选手打分，选手最后得分要去掉一个最高分，去掉一个最低分，然后求平均分作为选手成绩的功能，但不使用数组：

#include <stdio.h>
#include <limits.h>

int main() {
    int judge1, judge2, judge3, judge4, judge5;
    int highest, lowest, sum, avg;
    sum = 0;
    highest = INT_MIN; /* initialize as smallest value */
    lowest = INT_MAX; /* initialize as largest value */

    /* read in scores from the judges */
    printf("Enter score from judge 1: ");
    scanf("%d", &judge1);
    printf("Enter score from judge 2: ");
    scanf("%d", &judge2);
    printf("Enter score from judge 3: ");
    scanf("%d", &judge3);
    printf("Enter score from judge 4: ");
    scanf("%d", &judge4);
    printf("Enter score from judge 5: ");
    scanf("%d", &judge5);

    /* find the highest and lowest scores */
    if (judge1 > highest) {
        highest = judge1;
    }
    if (judge1 < lowest) {
        lowest = judge1;
    }
    if (judge2 > highest) {
        highest = judge2;
    }
    if (judge2 < lowest) {
        lowest = judge2;
    }
    if (judge3 > highest) {
        highest = judge3;
    }
    if (judge3 < lowest) {
        lowest = judge3;
    }
    if (judge4 > highest) {
        highest = judge4;
    }
    if (judge4 < lowest) {
        lowest = judge4;
    }
    if (judge5 > highest) {
        highest = judge5;
    }
    if (judge5 < lowest) {
        lowest = judge5;
    }

    /* calculate the sum of the scores */
    sum = judge1 + judge2 + judge3 + judge4 + judge5 - highest - lowest;

    /* calculate the average score */
    avg = sum / 3;

    /* print out the final score */
    printf("Final score: %d\n", avg);

    return 0;
}

希望这个代码能够满足您的需求。如果还有其他需要，请随时问我。