多线程猜数字 随机产生一个1000以内的整数 启动三个线程去自动猜 看哪个线程猜的次数最少 从低到高排序

以下是一个多线程猜数字的示例代码，可以实现随机产生一个1000以内的整数，启动三个线程去自动猜，并找出猜的次数最少的线程，并按照猜的次数从低到高排序：

import random
import threading

class GuessThread(threading.Thread):
    def __init__(self, name):
        threading.Thread.__init__(self)
        self.name = name
        self.count = 0

    def run(self):
        target_number = random.randint(1, 1000)
        guess_number = random.randint(1, 1000)
        while guess_number != target_number:
            self.count += 1
            guess_number = random.randint(1, 1000)
        print(f"{self.name} guessed the number {target_number} in {self.count} tries.")

if __name__ == '__main__':
    threads = []
    for i in range(3):
        thread = GuessThread(f"Thread-{i+1}")
        thread.start()
        threads.append(thread)

    for thread in threads:
        thread.join()

    sorted_threads = sorted(threads, key=lambda x: x.count)
    print("Sorted threads based on number of tries:")
    for thread in sorted_threads:
        print(f"{thread.name}: {thread.count} tries")

这段代码创建了三个线程，每个线程会随机生成一个目标数字和猜测数字，直到猜中为止，并记录猜的次数。最后，根据猜的次数对线程进行排序，并输出排序结果。

请注意，每次运行结果可能会不同，因为每个线程的猜测是随机的。