以上问题请提供代码或者伪代码
时间: 2023-07-03 19:19:53 浏览: 41
很抱歉,之前的回答没有提供伪代码,以下是使用二分归并法和哈夫曼算法实现文件归并的伪代码:
1. 二分归并法的伪代码:
```
mergeSort(arr[], l, r)
{
if (l < r)
{
//计算中间位置
int m = l+(r-l)/2;
//对左半部分进行排序
mergeSort(arr, l, m);
//对右半部分进行排序
mergeSort(arr, m+1, r);
//归并左右两部分
merge(arr, l, m, r);
}
}
merge(arr[], l, m, r)
{
//计算左右两部分的长度
int n1 = m - l + 1;
int n2 = r - m;
//创建临时数组
int L[n1], R[n2];
//将数据复制到临时数组中
for (int i = 0; i < n1; i++)
L[i] = arr[l + i];
for (int j = 0; j < n2; j++)
R[j] = arr[m + 1+ j];
//归并左右两部分
int i = 0, j = 0, k = l;
while (i < n1 && j < n2)
{
if (L[i] <= R[j])
{
arr[k] = L[i];
i++;
}
else
{
arr[k] = R[j];
j++;
}
k++;
}
//将剩余的元素复制到数组中
while (i < n1)
{
arr[k] = L[i];
i++;
k++;
}
while (j < n2)
{
arr[k] = R[j];
j++;
k++;
}
}
```
2. 哈夫曼算法的伪代码:
```
Huffman(S)
{
//计算每个文件的权重
for each file f in S
weight(f) = number of records in f
//创建哈夫曼树
while S has more than one file
select two files with smallest weight
create a new node with the sum of their weights
add the two files as children of the new node
add the new node to S
//获取哈夫曼编码
for each file f in S
code(f) = the path from the root to f
//按照哈夫曼编码进行归并
mergeFiles(S, code)
}
mergeFiles(S, code)
{
//按照哈夫曼编码进行顺序归并
while S has more than one file
select the file with the smallest code
append the records in the file to the output file
remove the file from S
}
```
以上是使用二分归并法和哈夫曼算法实现文件归并的伪代码,希望能够帮到您。