19、定义一个长度为10的整型数组，利用循环从键盘对其初始化。然后再输入一个整数n，在数组里面查找n，若找到则输出对应下标，若找不到则给出提醒。java

00x^5-2.00x^3+4.00x^2+1.00
Polynomial 2: 好的，这是 Java 语言的代码实现：

import java.util.Scanner;

public class Main {
    public static2.00x^4-3.00x^3+1.00x^2-1.00x
Sum:  void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        int[] arr = new int[10];
        // 从键盘输入初始化数组
        for (int i = 0; i < arr.length; i++) {
            System.out.print("3.00x^5+2.00x^4-5.00x^3+5.00x^2-1请输入第" + (i + 1) + "个整数：");
            arr[i] = scanner.nextInt();
        }
        System.00x
Difference: 3.00x^5-2.00x^4+1.00x^3+3.out.print("请输入要查找的整数：");
        int n = scanner.nextInt();
        // 在数组中查找元素n.00x^2+1.00x
Polynomial 1 value at x=2.00: 92.00
Pol
        int index = -1;
        for (int i = 0; i < arr.length; i++) {
            if (arr[i] == n) {
                index = i;
                break;
            }
        }
        // 输出结果
        if (index == -ynomial 2 value at x=2.00: 14.00
Sum value at x=2.00: 186.001) {
            System.out.println("在数组中未找到该元素！");
        } else {
            System.out.println("元素
Difference value at x=2.00: 102.00