解释一下:AccessibilityNodeInfo node = nodeInfos.get(0); if (node.isEnabled() && node.isClickable()) { node.performAction(AccessibilityNodeInfo.ACTION_CLICK);
时间: 2023-06-12 17:02:31 浏览: 143
这段代码首先获取了一个 `AccessibilityNodeInfo` 类型的对象 `node`,通过 `nodeInfos.get(0)` 获取的是一个集合中的第一个元素。`AccessibilityNodeInfo` 类型的对象是 Android 提供的一个类,用于描述应用程序界面中的元素,例如按钮、文本框等等。这个类提供了一些方法,可以获取该元素的一些属性,例如是否可用、是否可点击等等。
接下来的 `if` 语句中,判断了该元素是否可用,即调用 `isEnabled()` 方法,如果该方法返回 `true`,则表示该元素是可用的。这个方法的作用是返回该元素是否处于启用状态,如果该元素不可用,则调用它的方法将无效。如果该元素可用,则可以调用它的方法来与用户进行交互,例如点击该元素来触发相应的事件。
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boolean action1 = nodeInfo.performAction(AccessibilityNodeInfo.ACTION_CLICK); if (action1) { // 回收 nodeInfo.recycle(); printLogMsg(" 打开抖音极速版成功。" ); return true; } while (!nodeInfo.isClickable()) { nodeInfo = nodeInfo.getParent(); } if (nodeInfo.isClickable()) { boolean action = nodeInfo.performAction(AccessibilityNodeInfo.ACTION_CLICK); // 回收 nodeInfo.recycle(); return action; }
这段代码首先尝试执行AccessibilityNodeInfo节点的点击动作,并将结果赋值给action1。如果点击动作成功执行,会进行一些其他操作,然后返回true。
如果点击动作失败,代码会进入一个while循环,通过遍历节点的父节点来寻找一个可点击的节点。一旦找到可点击的节点,会再次尝试执行点击动作,并将结果赋值给action。最后,会回收节点并返回action的值。
public class MainActivity extends AppCompatActivity implements View.OnClickListener { private int[] cards = {R.drawable.card1, R.drawable.card2, R.drawable.card3, R.drawable.card1, R.drawable.card5, R.drawable.card6, R.drawable.card7, R.drawable.card8}; private int[] cardIds = {R.id.card1, R.id.card2, R.id.card3, R.id.card4, R.id.card5, R.id.card6, R.id.card7, R.id.card8}; private int[] cardStatus = new int[8]; private int firstCard = -1, secondCard = -1; private boolean isClickable = true; @Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_main); for (int i = 0; i < cardIds.length; i++) { ImageView card = findViewById(cardIds[i]); card.setTag(i); card.setOnClickListener(this); } Collections.shuffle(Arrays.asList(cards)); } @Override public void onClick(View v) { if (!isClickable) { return; } int id = (int) v.getTag(); if (cardStatus[id] == 1) { return; } if (firstCard == -1) { firstCard = id; ImageView card = findViewById(cardIds[id]); card.setImageResource(cards[id]); } else { secondCard = id; ImageView card = findViewById(cardIds[id]); card.setImageResource(cards[id]); if (cards[firstCard] == cards[secondCard]) { cardStatus[firstCard] = 1; cardStatus[secondCard] = 1; firstCard = -1; secondCard = -1; if (checkWin()) { Toast.makeText(this, "You Win!", Toast.LENGTH_SHORT).show(); } } else { isClickable = false; Handler handler = new Handler(); handler.postDelayed(new Runnable() { @Override public void run() { ImageView card1 = findViewById(cardIds[firstCard]); ImageView card2 = findViewById(cardIds[secondCard]); card1.setImageResource(R.drawable.card_back); card2.setImageResource(R.drawable.card_back); firstCard = -1; secondCard = -1; isClickable = true; } }, 1000); } } } private boolean checkWin() { for (int i = 0; i < cardStatus.length; i++) { if (cardStatus[i] == 0) { return false; } } return true; } }请帮我优化这段代码
以下是对代码的一些优化建议:
1. 将静态资源的ID和图片数组合并成一个Map,这样可以更方便地管理资源。
2. 将卡片点击事件的处理逻辑拆成两个方法,以提高代码可读性。
3. 将卡片的翻转和状态更新操作提炼成一个方法,以避免重复代码。
4. 将卡片匹配成功和失败的操作提炼成两个方法,以避免重复代码。
5. 使用Java 8的Stream API替换循环,以提高代码简洁性。
优化后的代码如下所示:
public class MainActivity extends AppCompatActivity implements View.OnClickListener {
private final Map<Integer, Integer> cardMap = new HashMap<>();
private final int[] cardIds = {R.id.card1, R.id.card2, R.id.card3, R.id.card4, R.id.card5, R.id.card6, R.id.card7, R.id.card8};
private final int[] cardStatus = new int[8];
private int firstCard = -1, secondCard = -1;
private boolean isClickable = true;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
Arrays.stream(cardIds).forEach(id -> {
ImageView card = findViewById(id);
card.setTag(id);
card.setOnClickListener(this);
});
cardMap.put(R.id.card1, R.drawable.card1);
cardMap.put(R.id.card2, R.drawable.card2);
cardMap.put(R.id.card3, R.drawable.card3);
cardMap.put(R.id.card4, R.drawable.card1);
cardMap.put(R.id.card5, R.drawable.card5);
cardMap.put(R.id.card6, R.drawable.card6);
cardMap.put(R.id.card7, R.drawable.card7);
cardMap.put(R.id.card8, R.drawable.card8);
Collections.shuffle(Arrays.asList(cardIds));
}
@Override
public void onClick(View v) {
if (!isClickable) {
return;
}
int id = (int) v.getTag();
if (cardStatus[id] == 1) {
return;
}
if (firstCard == -1) {
firstCard = id;
flipCard(v, cardMap.get(id));
} else {
secondCard = id;
flipCard(v, cardMap.get(id));
if (cardMap.get(firstCard).equals(cardMap.get(secondCard))) {
handleMatched();
} else {
handleMismatched();
}
}
}
private void flipCard(View v, int imageId) {
ImageView card = (ImageView) v;
card.setImageResource(imageId);
cardStatus[(int) v.getTag()] = 1;
}
private void handleMatched() {
cardStatus[firstCard] = 1;
cardStatus[secondCard] = 1;
firstCard = -1;
secondCard = -1;
if (checkWin()) {
Toast.makeText(this, "You Win!", Toast.LENGTH_SHORT).show();
}
}
private void handleMismatched() {
isClickable = false;
new Handler().postDelayed(() -> {
ImageView card1 = findViewById(firstCard);
ImageView card2 = findViewById(secondCard);
card1.setImageResource(R.drawable.card_back);
card2.setImageResource(R.drawable.card_back);
cardStatus[firstCard] = 0;
cardStatus[secondCard] = 0;
firstCard = -1;
secondCard = -1;
isClickable = true;
}, 1000);
}
private boolean checkWin() {
return Arrays.stream(cardStatus).allMatch(status -> status == 1);
}
}
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