on = on.drop_duplicates()

这是一个 Python 代码片段，用于去除列表中的重复元素。具体来说，它是将列表 on 转换为集合，然后再转回列表，这样就去除了重复元素。以下是完整的代码：

on = list(set(on))

希望这个回答能够帮到你！

相关问题

这两个方式求交集为什么结果不一样？方法一：df_merged2 = pd.merge(bp_rp, j_k, on=['RA', 'DEC'],how = "inner") 方法二：duplicates = ra_dec[ra_dec.duplicated()] df4=duplicates.drop_duplicates( subset=None, keep='first', inplace=False)

方法一和方法二的结果不一样的原因是两种方法对于重复值的处理方式不同。在方法一中，两个 DataFrame 按照列 'RA' 和 'DEC' 进行内连接，只保留两个 DataFrame 中都存在的行。而在方法二中，首先使用 `duplicates = ra_dec[ra_dec.duplicated()]` 选出重复的行，然后使用 `drop_duplicates()` 函数对这些重复行进行去重，保留其中的第一个（`keep='first'`）。

因此，如果 DataFrame 中存在多个相同的 'RA' 和 'DEC'，方法二会将其去重，只保留第一个出现的行；

优化代码 def cluster_format(self, start_time, end_time, save_on=True, data_clean=False, data_name=None): """ local format function is to format data from beihang. :param start_time: :param end_time: :return: """ # 户用簇级数据清洗 if data_clean: unused_index_col = [i for i in self.df.columns if 'Unnamed' in i] self.df.drop(columns=unused_index_col, inplace=True) self.df.drop_duplicates(inplace=True, ignore_index=True) self.df.reset_index(drop=True, inplace=True) dupli_header_lines = np.where(self.df['sendtime'] == 'sendtime')[0] self.df.drop(index=dupli_header_lines, inplace=True) self.df = self.df.apply(pd.to_numeric, errors='ignore') self.df['sendtime'] = pd.to_datetime(self.df['sendtime']) self.df.sort_values(by='sendtime', inplace=True, ignore_index=True) self.df.to_csv(data_name, index=False) # 调用基本格式化处理 self.df = super().format(start_time, end_time) module_number_register = np.unique(self.df['bat_module_num']) # if registered m_num is 0 and not changed, there is no module data if not np.any(module_number_register): logger.logger.warning("No module data!") sys.exit() if 'bat_module_voltage_00' in self.df.columns: volt_ref = 'bat_module_voltage_00' elif 'bat_module_voltage_01' in self.df.columns: volt_ref = 'bat_module_voltage_01' elif 'bat_module_voltage_02' in self.df.columns: volt_ref = 'bat_module_voltage_02' else: logger.logger.warning("No module data!") sys.exit() self.df.dropna(axis=0, subset=[volt_ref], inplace=True) self.df.reset_index(drop=True, inplace=True) self.headers = list(self.df.columns) # time duration of a cluster self.length = len(self.df) if self.length == 0: logger.logger.warning("After cluster data clean, no effective data!") raise ValueError("No effective data after cluster data clean.") self.cluster_stats(save_on) for m in range(self.mod_num): print(self.clusterid, self.mod_num) self.module_list.append(np.unique(self.df[f'bat_module_sn_{str(m).zfill(2)}'].dropna())[0])

Here are some possible optimizations for the given code:

1. Instead of using a list comprehension to find columns with 'Unnamed' in their names, you can use the `filter()` function along with a lambda function to achieve the same result in a more concise way:

   unused_index_col = list(filter(lambda x: 'Unnamed' in x, self.df.columns))

2. Instead of dropping duplicates and resetting the index separately, you can use the `drop_duplicates()` function with the `ignore_index` parameter set to `True` to achieve both in one step:

   self.df.drop_duplicates(inplace=True, ignore_index=True)

3. Instead of using `sys.exit()` to terminate the program when there is no module data, you can raise a `ValueError` with an appropriate error message:

   raise ValueError("No module data!")

4. Instead of using a series of `if` statements to find the voltage reference column, you can use the `loc` accessor with a boolean mask to select the first column that starts with 'bat_module_voltage':

   volt_ref_col = self.df.columns[self.df.columns.str.startswith('bat_module_voltage')][0]

5. Instead of using a loop to append a single item to a list, you can use the `append()` method directly:

   self.module_list.append(np.unique(self.df[f'bat_module_sn_{str(m).zfill(2)}'].dropna())[0])

By applying these optimizations, the code can become more concise and efficient.