cash_loan = mydata[mydata['NAME_CONTRACT_TYPE'] == 'Cash loans']

时间: 2024-03-31 15:35:38 浏览: 9
您的第一个问题是关于 Python 语言的代码,其中使用了 pandas 库对数据进行筛选。根据您提供的代码,这行代码的作用是选取一个名为 mydata 的数据集中,名为 NAME_CONTRACT_TYPE 的列等于 'Cash loans' 的所有行,并将结果赋值给变量 cash_loan。换句话说,这行代码筛选出了 mydata 数据集中所有贷款类型为“现金贷款”的行。
相关问题

修正下列代码并完善它 #include<stdio.h> int main(void) { int python,math,english,physical_education,military_theory,philosophy python = 3; math = 4; english = 4; physical_education= 2; military_theory = 2; philosophy = 2; scanf("%d,%d,%d,%d,%d,%d",&python,&math,&english,&physical_education,&military_theory,&philosophy); tuition_per_credit = int(input()); total_credits = (python + math + english + physical_education + military_theory + philosophy); total_tuition = total_credits * tuition_per_credit; living_expenses = float(input()); total_cost = living_expenses * 5 + total_tuition; student_loan = total_cost * 0.6; printf("student_loan "); return 0; }

以下是修正后的代码: ``` #include<stdio.h> int main(void) { int python, math, english, physical_education, military_theory, philosophy; float tuition_per_credit, living_expenses, total_cost, student_loan; printf("请输入 Python 成绩、数学成绩、英语成绩、体育成绩、军事理论成绩和哲学成绩(以逗号分隔):"); scanf("%d,%d,%d,%d,%d,%d", &python, &math, &english, &physical_education, &military_theory, &philosophy); printf("请输入每学分的学费:"); scanf("%f", &tuition_per_credit); int total_credits = python + math + english + physical_education + military_theory + philosophy; float total_tuition = total_credits * tuition_per_credit; printf("请输入每月生活费用:"); scanf("%f", &living_expenses); total_cost = living_expenses * 5 + total_tuition; student_loan = total_cost * 0.6; printf("你需要申请 %.2f 元的学生贷款\n", student_loan); return 0; } ``` 主要修正包括: 1. 添加了变量的声明,包括 `tuition_per_credit`、`living_expenses`、`total_cost` 和 `student_loan`; 2. 修改了 `scanf` 函数中的格式化字符串,使其与输入的变量类型匹配; 3. 添加了用户输入的提示信息; 4. 修改了输出语句,使其输出正确的结果。

select customer_name, borrower.loan_number, amount from borrower, loan where borrower.loan_number = loan.loan_number and branch_name = 'Perryridge’. What is the meaning of the borrower.loan_number = loan.loan_number。请用中文解释

"borrower.loan_number = loan.loan_number" 是一个连接条件。它指定了如何将 "borrower" 表和 "loan" 表连接起来以从两个表中检索数据。 具体来说,它表示应该将 "borrower" 表中的 "loan_number" 列与 "loan" 表中的 "loan_number" 列进行比较,只有这些值匹配的行才会包含在结果集中。换句话说,这个条件确保只返回从 "Perryridge" 分行借贷的客户的姓名、贷款编号和贷款金额。

相关推荐

请将这个存储过程修改为触发器,当其余四个表插入新数据时,t_pcm_prod_own能够修改更新数据 CREATE DEFINER=root@% PROCEDURE test03() BEGIN -- 是否持有活期 IF EXISTS(SELECT CUST_ID FROM T_PCM_PROD_OWN WHERE CUST_ID IN (SELECT CUST_ID FROM T_PCM_DEP_CURR)) THEN UPDATE T_PCM_PROD_OWN SET IS_DEP = '1' WHERE CUST_ID IN (SELECT CUST_ID FROM T_PCM_DEP_CURR); ELSE UPDATE T_PCM_PROD_OWN SET IS_DEP = '0' WHERE CUST_ID IN (SELECT CUST_ID FROM T_PCM_DEP_CURR); END IF; -- 是否持有定期 IF EXISTS(SELECT CUST_ID FROM T_PCM_PROD_OWN WHERE CUST_ID IN (SELECT CUST_ID FROM T_PCM_DEP_FIXED)) THEN UPDATE T_PCM_PROD_OWN SET IS_FIXED_DEP = '1' WHERE CUST_ID IN (SELECT CUST_ID FROM T_PCM_DEP_FIXED); ELSE UPDATE T_PCM_PROD_OWN SET IS_FIXED_DEP = '0' WHERE CUST_ID IN (SELECT CUST_ID FROM T_PCM_DEP_FIXED); END IF; -- 是否持有贷款 IF EXISTS(SELECT CUST_ID FROM T_PCM_PROD_OWN WHERE CUST_ID IN (SELECT CUST_ID FROM T_PCM_LOAN)) THEN UPDATE T_PCM_PROD_OWN SET IS_LOAN = '1' WHERE CUST_ID IN (SELECT CUST_ID FROM T_PCM_LOAN); ELSE UPDATE T_PCM_PROD_OWN SET IS_LOAN = '0' WHERE CUST_ID IN (SELECT CUST_ID FROM T_PCM_LOAN); END IF; -- 是否持有理财 IF EXISTS(SELECT CUST_ID FROM T_PCM_PROD_OWN WHERE CUST_ID IN (SELECT CUST_ID FROM T_PCM_WEALTH)) THEN UPDATE T_PCM_PROD_OWN SET IS_WEALTH = '1' WHERE CUST_ID IN (SELECT CUST_ID FROM T_PCM_WEALTH); ELSE UPDATE T_PCM_PROD_OWN SET IS_WEALTH = '0' WHERE CUST_ID IN (SELECT CUST_ID FROM T_PCM_WEALTH); END IF; INSERT INTO T_PCM_PROD_OWN SELECT REPLACE(UUID(),'-','') ,T_PCM_CUST.CUST_ID ,T_PCM_CUST.LAW_ORG_ID ,T_PCM_CUST.ECIF_CUST_ID ,T_PCM_PROD_OWN.IS_DEP ,T_PCM_PROD_OWN.IS_FIXED_DEP ,T_PCM_PROD_OWN.IS_LOAN ,T_PCM_PROD_OWN.IS_WEALTH ,T_PCM_DEP_CURR.CURRENT_BAL ,T_PCM_DEP_FIXED.BAL ,T_PCM_LOAN.LOAN_MON ,T_PCM_WEALTH.CURRENT_BAL FROM T_PCM_CUST LEFT JOIN T_PCM_DEP_CURR ON T_PCM_CUST.CUST_ID = T_PCM_DEP_CURR.CUST_ID LEFT JOIN T_PCM_DEP_FIXED ON T_PCM_CUST.CUST_ID = T_PCM_DEP_FIXED.CUST_ID LEFT JOIN T_PCM_LOAN ON T_PCM_CUST.CUST_ID = T_PCM_LOAN.CUST_ID LEFT JOIN T_PCM_WEALTH ON T_PCM_CUST.CUST_ID = T_PCM_WEALTH.CUST_ID LEFT JOIN T_PCM_PROD_OWN ON T_PCM_CUST.CUST_ID = T_PCM_PROD_OWN.CUST_ID; END

优化下这个代码 select sum(auth_amt) sum_auth_amt from auth_cont auth left join (select * from RPT_DUE_LOAN_ACC_M loan where loan.send_flag = '2' and loan.prd_userdf_type != '3017' and loan.bank_id = 162000 and (loan.cif_no in (select cif_no from RPT_DUE_LOAN_ACC_M a where 1 = 1 AND LOAN.YEAR = '2021' AND LOAN.MONTH = '12' AND LOAN.ACCOUNT_STATUS NOT IN ('0', '2') AND ((LOAN.LOAN_BAL > 0 OR LOAN.IN_INTST > 0 OR LOAN.OUT_INTST > 0 OR LOAN.CMPD_INTST > 0) or substr(LOAN.SETTL_DATE, 0, 6) = '202112') AND LOAN.MANG_BR_NO IN (SELECT BR_NO FROM TBL_ORG_DEPARTMENTS START WITH BR_NO = '162000' CONNECT BY PRIOR BR_NO = UP_ONE) group by cif_no and (loan.cif_no in (select cif_no from RPT_DUE_LOAN_ACC_M a where 1 = 1 AND LOAN.YEAR = '2021' AND LOAN.MONTH = '12' AND LOAN.ACCOUNT_STATUS NOT IN ('0', '2') AND ((LOAN.LOAN_BAL > 0 OR LOAN.IN_INTST > 0 OR LOAN.OUT_INTST > 0 OR LOAN.CMPD_INTST > 0) or substr(LOAN.SETTL_DATE, 0, 6) = '202112') AND LOAN.MANG_BR_NO IN (SELECT BR_NO FROM TBL_ORG_DEPARTMENTS START WITH BR_NO = '162000' CONNECT BY PRIOR BR_NO = UP_ONE) group by cif_no group by cif_no) loan on loan.cif_no = auth.cif_no where auth_sts = '1' AND LOAN.YEAR = '2021' AND LOAN.MONTH = '12' AND LOAN.ACCOUNT_STATUS NOT IN ('0', '2') AND ((LOAN.LOAN_BAL > 0 OR LOAN.IN_INTST > 0 OR LOAN.OUT_INTST > 0 OR LOAN.CMPD_INTST > 0) or substr(LOAN.SETTL_DATE, 0, 6) = '202112') AND LOAN.MANG_BR_NO IN (SELECT BR_NO FROM TBL_ORG_DEPARTMENTS START WITH BR_NO = '162000' CONNECT BY PRIOR BR_NO = UP_ONE)

在python中用函数优化以下代码while True: print('='*30) loan_type = input('请选择贷款类型:1.商业贷款 2.公积金贷款 3.组合贷款 0.算清楚了谢谢\n') if loan_type == '1' : loan_amount = float(input('请输入贷款金额(万)\n')) term = int(input('请输入贷款期限(年):\n')) if term <= 5 : mon_rate = (4.75 / 100) / 12 else: mon_rate = (4.90 / 100) / 12 mon_pay = loan_amount * 10000 * (mon_rate * ((1+mon_rate)**(term * 12))) / (((1 + mon_rate)** (term * 12)) - 1) all_pay = mon_pay * term * 12 interest = all_pay - loan_amount * 10000 print('每月月供参考(元):{:.2f}'.format(mon_pay)) print('支付利息(元):{:.2f}'.format(interest)) print('还款总额(元):{:.2f}'.format(all_pay)) elif loan_type == '2' : loan_amount = float(input('请输入贷款金额(万):\n')) term = int(input('请输入贷款期限(年):\n')) if term <= 5 : mon_rate = (2.75 / 100) / 12 else: mon_rate = (3.25 / 100) / 12 mon_pay = loan_amount * 10000 * (mon_rate * ((1 + mon_rate) ** (term * 12))) / (((1 + mon_rate)** (term * 12)) - 1) all_pay = mon_pay * term * 12 interest = all_pay - loan_amount * 10000 print('每月月供参考(元):{:.2f}'.format(mon_pay)) print('支付利息(元):{:.2f}'.format(interest)) print('还款总额(元):{:.2f}'.format(all_pay)) elif loan_type == '3': business_loan = float(input('请输入商业贷款金额(万):\n')) fund_loan = int(input('请输入公积金贷款金额(万):\n')) term = int(input('请输入贷款期限(年):\n')) if term <= 5: business_mon_rate = (4.75 / 100) / 12 fund_mon_rate = (2.75 / 100) / 12 else: business_loan = (4.90 / 100) / 12 fund_mon_rate = (3.25 / 100) / 12 business_mon_pay = business_loan * 10000 * (business_mon_rate * ((1 + business_mon_rate) ** (term * 12))) / (((1 + business_mon_rate)** (term * 12)) - 1) fund_mon_pay = fund_loan * 10000 * (fund_mon_rate * ((1 + fund_mon_rate) ** (term * 12))) / (((1 + fund_mon_rate) ** (term * 12)) - 1) mon_all_pay = business_mon_pay + fund_mon_pay all

最新推荐

recommend-type

华为OD机试D卷 - 用连续自然数之和来表达整数 - 免费看解析和代码.html

私信博主免费获取真题解析以及代码
recommend-type

Screenshot_2024-05-10-20-21-01-857_com.chaoxing.mobile.jpg

Screenshot_2024-05-10-20-21-01-857_com.chaoxing.mobile.jpg
recommend-type

zigbee-cluster-library-specification

最新的zigbee-cluster-library-specification说明文档。
recommend-type

管理建模和仿真的文件

管理Boualem Benatallah引用此版本:布阿利姆·贝纳塔拉。管理建模和仿真。约瑟夫-傅立叶大学-格勒诺布尔第一大学,1996年。法语。NNT:电话:00345357HAL ID:电话:00345357https://theses.hal.science/tel-003453572008年12月9日提交HAL是一个多学科的开放存取档案馆,用于存放和传播科学研究论文,无论它们是否被公开。论文可以来自法国或国外的教学和研究机构,也可以来自公共或私人研究中心。L’archive ouverte pluridisciplinaire
recommend-type

实现实时数据湖架构:Kafka与Hive集成

![实现实时数据湖架构:Kafka与Hive集成](https://img-blog.csdnimg.cn/img_convert/10eb2e6972b3b6086286fc64c0b3ee41.jpeg) # 1. 实时数据湖架构概述** 实时数据湖是一种现代数据管理架构,它允许企业以低延迟的方式收集、存储和处理大量数据。与传统数据仓库不同,实时数据湖不依赖于预先定义的模式,而是采用灵活的架构,可以处理各种数据类型和格式。这种架构为企业提供了以下优势: - **实时洞察:**实时数据湖允许企业访问最新的数据,从而做出更明智的决策。 - **数据民主化:**实时数据湖使各种利益相关者都可
recommend-type

spring添加xml配置文件

1. 创建一个新的Spring配置文件,例如"applicationContext.xml"。 2. 在文件头部添加XML命名空间和schema定义,如下所示: ``` <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.springframework.org/schema/beans
recommend-type

JSBSim Reference Manual

JSBSim参考手册,其中包含JSBSim简介,JSBSim配置文件xml的编写语法,编程手册以及一些应用实例等。其中有部分内容还没有写完,估计有生之年很难看到完整版了,但是内容还是很有参考价值的。
recommend-type

"互动学习:行动中的多样性与论文攻读经历"

多样性她- 事实上SCI NCES你的时间表ECOLEDO C Tora SC和NCESPOUR l’Ingén学习互动,互动学习以行动为中心的强化学习学会互动,互动学习,以行动为中心的强化学习计算机科学博士论文于2021年9月28日在Villeneuve d'Asq公开支持马修·瑟林评审团主席法布里斯·勒菲弗尔阿维尼翁大学教授论文指导奥利维尔·皮耶昆谷歌研究教授:智囊团论文联合主任菲利普·普雷教授,大学。里尔/CRISTAL/因里亚报告员奥利维耶·西格德索邦大学报告员卢多维奇·德诺耶教授,Facebook /索邦大学审查员越南圣迈IMT Atlantic高级讲师邀请弗洛里安·斯特鲁布博士,Deepmind对于那些及时看到自己错误的人...3谢谢你首先,我要感谢我的两位博士生导师Olivier和Philippe。奥利维尔,"站在巨人的肩膀上"这句话对你来说完全有意义了。从科学上讲,你知道在这篇论文的(许多)错误中,你是我可以依
recommend-type

实现实时监控告警系统:Kafka与Grafana整合

![实现实时监控告警系统:Kafka与Grafana整合](https://imgconvert.csdnimg.cn/aHR0cHM6Ly9tbWJpei5xcGljLmNuL21tYml6X2pwZy9BVldpY3ladXVDbEZpY1pLWmw2bUVaWXFUcEdLT1VDdkxRSmQxZXB5R1lxaWNlUjA2c0hFek5Qc3FyRktudFF1VDMxQVl3QTRXV2lhSWFRMEFRc0I1cW1ZOGcvNjQw?x-oss-process=image/format,png) # 1.1 Kafka集群架构 Kafka集群由多个称为代理的服务器组成,这
recommend-type

输出这段Python代码输出所有3位整数中,个位是5且是3的倍数的整数

``` for i in range(100,1000): if i%10 == 5 and i%3 == 0: print(i) ``` 输出结果: ``` 105 135 165 195 225 255 285 315 345 375 405 435 465 495 525 555 585 615 645 675 705 735 765 795 825 855 885 915 945 975 ```