s1=”我喜欢”s2="Python"请基于Python计算s1+s2 s1*2 3*s2 s1*s2 "我"in s1 s1[0] s1[-3:-1] s1[∷-1] s2[∷2] s2[1∷2] s1>s2

s1 = "我喜欢"
s2 = "Python"

s1 + s2 = "我喜欢Python"
s1 * 2 = "我喜欢我喜欢"
3 * s2 = "PythonPythonPython"
s1 * s2 = TypeError: can't multiply sequence by non-int of type 'str'
"我" in s1 = True
s1[0] = "我"
s1[-3:-1] = "喜欢"
s1[:: -1] = "欢喜我"
s2[::2] = "Pto"
s2[1::2] = "yh"

s1 > s2 = False

相关问题

s1=我喜欢 s2=python s1*s2=

根据提供的引用内容，s1和s2都是字符串类型，不能进行乘法运算。如果要将两个字符串拼接起来，可以使用"+"运算符或者字符串的join()方法。例如：

s1 = "我喜欢"
s2 = "python"
s3 = s1 + s2
print(s3) # 输出：我喜欢python

或者使用join()方法：

s1 = "我喜欢"
s2 = "python"
s3 = "".join([s1, s2])
print(s3) # 输出：我喜欢python

for a in range (1,10): for b in range (1,10): for c in range (1,10): s1=a*100+b*10+c s2=a**3+b**3+c**3 if s1==s2: print (s1)

This code is written in Python and it prints out all the Armstrong numbers between 100 and 999.

An Armstrong number is a number that is equal to the sum of its own digits raised to the power of the number of digits in the number.

For example, 153 is an Armstrong number because:

1^3 + 5^3 + 3^3 = 1 + 125 + 27 = 153

The code uses three nested loops to generate all three-digit numbers from 100 to 999. For each number, it calculates the sum of its digits raised to the third power and compares it to the original number. If they are equal, it prints out the number.

So, the output of this code will be:

153
370
371
407

These are the four Armstrong numbers between 100 and 999.