编写程序输出0。~180。之间, 步长为15。时各度数的sin和cos函数。

以下是 Python 代码实现：

import math

for i in range(0, 181, 15):
    sin_val = math.sin(i * math.pi / 180)
    cos_val = math.cos(i * math.pi / 180)
    print(f"sin({i}) = {sin_val:.4f}, cos({i}) = {cos_val:.4f}")

输出结果为：

sin(0) = 0.0000, cos(0) = 1.0000
sin(15) = 0.2588, cos(15) = 0.9659
sin(30) = 0.5000, cos(30) = 0.8660
sin(45) = 0.7071, cos(45) = 0.7071
sin(60) = 0.8660, cos(60) = 0.5000
sin(75) = 0.9659, cos(75) = 0.2588
sin(90) = 1.0000, cos(90) = 0.0000
sin(105) = 0.9659, cos(105) = -0.2588
sin(120) = 0.8660, cos(120) = -0.5000
sin(135) = 0.7071, cos(135) = -0.7071
sin(150) = 0.5000, cos(150) = -0.8660
sin(165) = 0.2588, cos(165) = -0.9659
sin(180) = 0.0000, cos(180) = -1.0000