请你使用x86汇编语言编写
时间: 2023-08-04 16:05:29 浏览: 115
pingjunfen.zip_汇编语言_Asm_
好的,以下是x86汇编代码:
```
section .data
msg db 'Enter an integer between 0 and 20: $'
summsg db 'The sum of cubes from 0 to %d is %d$'
nl db 0dh, 0ah, '$'
x db ?
sum dw 0
section .text
global _start
_start:
; print message and read input
mov eax, 4 ; system call for write
mov ebx, 1 ; file descriptor for stdout
mov ecx, msg
mov edx, 31 ; message length
int 0x80
mov eax, 3 ; system call for read
mov ebx, 0 ; file descriptor for stdin
mov ecx, x
mov edx, 1 ; number of bytes to read
int 0x80
sub byte [x], '0' ; convert character to number
; calculate sum of cubes
xor ecx, ecx ; clear ecx
mov ax, 0 ; clear ax
loop1:
cmp cl, [x]
jg done
push ecx ; save ecx on stack
mov ebx, ecx
mov ax, cx ; calculate cube of cx
mul cx
mul bx
add [sum], ax ; add cube to sum
pop ecx ; restore ecx
inc cl ; increment ecx
jmp loop1
done:
; print sum of cubes
mov eax, 4 ; system call for write
mov ebx, 1 ; file descriptor for stdout
mov ecx, nl
mov edx, 2 ; message length
int 0x80
mov eax, 4 ; system call for write
mov ebx, 1 ; file descriptor for stdout
mov ecx, summsg
mov edx, 31 ; message length
int 0x80
mov eax, [sum] ; move sum to eax
mov ebx, 10 ; set ebx to 10
xor ecx, ecx ; clear ecx
xor edx, edx ; clear edx
loop2:
div ebx ; divide eax by 10
add edx, '0' ; convert remainder to character
push edx ; push remainder onto stack
inc cl ; increment ecx
cmp eax, 0 ; check if quotient is zero
jne loop2
print:
pop edx ; pop remainder from stack
mov eax, 4 ; system call for write
mov ebx, 1 ; file descriptor for stdout
mov ecx, edx
mov edx, 1 ; message length
int 0x80
loop print ; loop until stack is empty
mov eax, 1 ; system call for exit
xor ebx, ebx ; exit status
int 0x80
```
这个程序与之前的程序非常相似,只不过使用了x86汇编语言,并使用了Linux系统调用来进行输入和输出。请注意,Linux系统调用使用`int 0x80`指令来触发,而不是`int 21h`。
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