c语言使用谱减法处理wav音频数据例子
时间: 2023-12-02 14:06:14 浏览: 140
好的,以下是一段使用C语言进行谱减法处理wav音频数据的例子代码:
```
#include <stdio.h>
#include <stdlib.h>
#include <stdint.h>
#include <math.h>
#define PI 3.14159265358979323846
typedef struct {
uint16_t formatTag;
uint16_t channels;
uint32_t samplesPerSec;
uint32_t bytesPerSec;
uint16_t blockAlign;
uint16_t bitsPerSample;
uint32_t dataSize;
uint8_t* data;
} WaveFile;
float hannWindow(int n, int N) {
return 0.5 * (1 - cos(2 * PI * n / (N - 1)));
}
void stft(float* x, int N, int H, float* X, int M, float* w) {
int i, j, k;
float re, im, tmp;
for (i = 0; i < M; i++) {
for (j = 0; j < N; j++) {
k = i * H + j;
if (k >= (N + (M - 1) * H)) {
break;
}
tmp = x[k] * w[j];
re = tmp * cos(2 * PI * j / N);
im = tmp * sin(2 * PI * j / N);
X[i * (N / 2 + 1) + j] = sqrt(re * re + im * im);
}
}
}
void specSubtraction(float* X, int N, int M, float alpha, float beta, float* Y) {
int i, j;
for (i = 0; i < M; i++) {
for (j = 0; j <= N / 2; j++) {
Y[i * (N / 2 + 1) + j] = fmax(X[i * (N / 2 + 1) + j] - alpha * beta * X[j], 0);
}
}
}
void istft(float* X, int N, int H, float* x, int M, float* w) {
int i, j, k, L;
float re, im, tmp;
for (i = 0; i < M; i++) {
for (j = 0; j < N; j++) {
k = i * H + j;
if (k >= (N + (M - 1) * H)) {
break;
}
tmp = X[i * (N / 2 + 1) + j];
re = tmp * cos(2 * PI * j / N);
im = tmp * sin(2 * PI * j / N);
x[k] += re * w[j];
}
}
for (i = 0; i < N; i++) {
x[i] /= w[i];
}
}
void readWaveFile(char* fileName, WaveFile* wf) {
FILE* fp;
uint32_t readSize;
fp = fopen(fileName, "rb");
if (!fp) {
printf("Failed to open file: %s\n", fileName);
exit(1);
}
fread(&wf->formatTag, 2, 1, fp);
fread(&wf->channels, 2, 1, fp);
fread(&wf->samplesPerSec, 4, 1, fp);
fread(&wf->bytesPerSec, 4, 1, fp);
fread(&wf->blockAlign, 2, 1, fp);
fread(&wf->bitsPerSample, 2, 1, fp);
fseek(fp, 40, SEEK_SET);
fread(&wf->dataSize, 4, 1, fp);
wf->data = (uint8_t*)malloc(wf->dataSize);
fread(wf->data, wf->dataSize, 1, fp);
fclose(fp);
}
void writeWaveFile(char* fileName, WaveFile wf) {
FILE* fp;
uint32_t dataSize;
uint8_t* data;
uint16_t bytePerSample;
bytePerSample = wf.bitsPerSample / 8;
dataSize = wf.channels * wf.dataSize / bytePerSample;
data = (uint8_t*)malloc(dataSize);
memset(data, 0, dataSize);
if (wf.formatTag == 1) {
if (wf.bitsPerSample == 8) {
int8_t* p = (int8_t*)wf.data;
int16_t* q = (int16_t*)data;
int i;
for (i = 0; i < wf.dataSize; i++) {
*q++ = ((int16_t)(*p++)) << 8;
}
} else if (wf.bitsPerSample == 16) {
memcpy(data, wf.data, wf.dataSize);
}
}
fp = fopen(fileName, "wb");
if (!fp) {
printf("Failed to open file: %s\n", fileName);
exit(1);
}
fwrite("RIFF", 4, 1, fp);
fwrite(&dataSize, 4, 1, fp);
fwrite("WAVE", 4, 1, fp);
fwrite("fmt ", 4, 1, fp);
fwrite("\x10\x00\x00\x00", 4, 1, fp);
fwrite("\x01\x00", 2, 1, fp);
fwrite(&wf.channels, 2, 1, fp);
fwrite(&wf.samplesPerSec, 4, 1, fp);
fwrite(&wf.bytesPerSec, 4, 1, fp);
fwrite(&wf.blockAlign, 2, 1, fp);
fwrite(&wf.bitsPerSample, 2, 1, fp);
fwrite("data", 4, 1, fp);
fwrite(&dataSize, 4, 1, fp);
fwrite(data, dataSize, 1, fp);
fclose(fp);
free(data);
}
void freeWaveFile(WaveFile wf) {
free(wf.data);
}
int main(int argc, char* argv[]) {
WaveFile wf;
int N, M, H;
float* x, * y, * X, * Y, * w;
float alpha, beta;
int i;
if (argc < 2) {
printf("Usage: %s <input file>\n", argv[0]);
exit(1);
}
readWaveFile(argv[1], &wf);
N = 256;
M = wf.dataSize / 2 / (N / 2);
H = N / 2;
alpha = 2;
beta = 0.9;
x = (float*)calloc(N + (M - 1) * H, sizeof(float));
memcpy(x, wf.data, wf.dataSize);
w = (float*)calloc(N, sizeof(float));
for (i = 0; i < N; i++) {
w[i] = hannWindow(i, N);
}
X = (float*)calloc(M * (N / 2 + 1), sizeof(float));
Y = (float*)calloc(M * (N / 2 + 1), sizeof(float));
stft(x, N, H, X, M, w);
specSubtraction(X, N, M, alpha, beta, Y);
istft(Y, N, H, x, M, w);
wf.dataSize = (N + (M - 1) * H) * wf.channels * wf.bitsPerSample / 8;
memcpy(wf.data, x, wf.dataSize);
writeWaveFile("output.wav", wf);
free(x);
free(w);
free(X);
free(Y);
freeWaveFile(wf);
return 0;
}
```
同时需要注意的是,该例子仅供参考,请根据实际情况进行修改和适当调整。
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