Using the LDR and STR instructions, write a simple ARM assembly code snippet to copy the content of memory location 0x30000000 to memory location 0x40000000. Assume r0, r1, and r2 are available for use.
时间: 2024-02-01 18:04:36 浏览: 95
Here is a simple ARM assembly code snippet that uses LDR and STR instructions to copy the content of memory location 0x30000000 to memory location 0x40000000:
```arm
; Copy the content of memory location 0x30000000 to memory location 0x40000000
ldr r0, =0x30000000 ; Load the source address to register r0
ldr r1, [r0] ; Load the data from the source address to register r1
ldr r0, =0x40000000 ; Load the destination address to register r0
str r1, [r0] ; Store the data to the destination address from register r1
```
In this code snippet, we first load the source address 0x30000000 to register r0 using the LDR instruction with an immediate value. Then, we load the data from the source address to register r1 using the LDR instruction with the indirect addressing mode [r0]. Next, we load the destination address 0x40000000 to register r0 using the LDR instruction with an immediate value. Finally, we store the data from register r1 to the destination address using the STR instruction with the indirect addressing mode [r0].
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