用python写个扫雷游戏

可以的，我可以为您提供一个简单的代码示例，如下所示：

import random

def create_board(rows, cols, num_mines):
    # Create an empty board
    board = [[0 for col in range(cols)] for row in range(rows)]

    # Add mines to the board
    mines = 0
    while mines < num_mines:
        row = random.randint(0, rows - 1)
        col = random.randint(0, cols - 1)
        if board[row][col] != -1:
            board[row][col] = -1
            mines += 1

    # Fill in the numbers around the mines
    for row in range(rows):
        for col in range(cols):
            if board[row][col] == -1:
                # Add 1 to each adjacent square
                for i in range(-1, 2):
                    for j in range(-1, 2):
                        if 0 <= row + i < rows and 0 <= col + j < cols and board[row + i][col + j] != -1:
                            board[row + i][col + j] += 1

    return board

def print_board(board):
    rows = len(board)
    cols = len(board[0])

    # Print the column numbers
    print("  ", end="")
    for col in range(cols):
        print(col, end=" ")
    print("")

    # Print the board
    for row in range(rows):
        print(row, end=" ")
        for col in range(cols):
            if board[row][col] == -1:
                print("*", end=" ")
            elif board[row][col] == 0:
                print(".", end=" ")
            else:
                print(board[row][col], end=" ")
        print("")

def reveal(board, revealed, row, col):
    if revealed[row][col]:
        return

    rows = len(board)
    cols = len(board[0])

    # Reveal the square and continue recursively if it's a zero
    revealed[row][col] = True
    if board[row][col] == 0:
        for i in range(-1, 2):
            for j in range(-1, 2):
                if 0 <= row + i < rows and 0 <= col + j < cols:
                    reveal(board, revealed, row + i, col + j)

def play_game():
    rows = int(input("Enter the number of rows: "))
    cols = int(input("Enter the number of columns: "))
    num_mines = int(input("Enter the number of mines: "))

    board = create_board(rows, cols, num_mines)
    revealed = [[False for col in range(cols)] for row in range(rows)]

    while True:
        print_board(revealed)

        row = int(input("Enter a row: "))
        col = int(input("Enter a column: "))

        if board[row][col] == -1:
            print("You hit a mine! Game over.")
            break
        else:
            reveal(board, revealed, row, col)

        # Check if the game is won
        if all(all(revealed[row][col] or board[row][col] == -1 for col in range(cols)) for row in range(rows)):
            print_board(board)
            print("You win!")
            break

play_game()

该脚本将使用Python语言实现一个简单的扫雷游戏。用户将输入行数、列数和地雷数量，游戏板将被创建并显示。玩家可以选择一个单元格来揭开，如果点击地雷则游戏失败，如果玩家成功在未触雷的情况下揭示了所有方格，则获胜。