基于边界的目标表达链码算法python
时间: 2023-12-20 17:04:15 浏览: 74
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下面是基于边界的目标表达链码算法的Python实现:
```python
import numpy as np
def boundary_following(image):
"""
基于边界的目标表达链码算法
:param image: 二值化的图像矩阵,0表示背景,1表示前景
:return: 链码
"""
# 找到起点
start_x, start_y = np.nonzero(image)[0][0], np.nonzero(image)[1][0]
x, y = start_x, start_y
chain_code = []
direction = 7 # 初始方向为7,即左上方
while True:
# 记录当前位置的链码
chain_code.append(direction)
# 沿当前方向移动一步
if direction in [0, 1, 2]:
x -= 1
elif direction == 3:
x -= 1
y += 1
elif direction in [4, 5, 6]:
y += 1
else:
x += 1
y += 1
# 如果回到起点,则停止追踪
if x == start_x and y == start_y:
break
# 根据当前位置和方向确定下一个方向
if direction == 0:
if image[x-1, y] == 1:
direction = 0
elif image[x-1, y+1] == 1:
direction = 1
else:
direction = 2
elif direction == 1:
if image[x-1, y+1] == 1:
direction = 1
elif image[x, y+1] == 1:
direction = 2
else:
direction = 3
elif direction == 2:
if image[x, y+1] == 1:
direction = 2
elif image[x+1, y+1] == 1:
direction = 3
else:
direction = 4
elif direction == 3:
if image[x+1, y+1] == 1:
direction = 3
elif image[x+1, y] == 1:
direction = 4
else:
direction = 5
elif direction == 4:
if image[x+1, y] == 1:
direction = 4
elif image[x+1, y-1] == 1:
direction = 5
else:
direction = 6
elif direction == 5:
if image[x+1, y-1] == 1:
direction = 5
elif image[x, y-1] == 1:
direction = 6
else:
direction = 7
else:
if image[x, y-1] == 1:
direction = 6
elif image[x-1, y-1] == 1:
direction = 7
else:
direction = 0
return chain_code
```
上述代码中,我们先找到起点,然后根据当前位置和方向确定下一个方向,并沿着下一个方向移动一步,直到回到起点。在移动的过程中,记录每个位置的链码。具体实现中,我们用一个while循环来完成这个过程,并使用一个direction变量来表示当前方向。在每次移动之前,先记录当前位置的链码,然后根据当前位置和方向确定下一个方向,最后沿着下一个方向移动一步。
需要注意的是,在确定下一个方向的过程中,我们需要判断下一个位置是否是前景(即是否等于1),如果是前景,则继续沿当前方向移动;否则,根据当前方向,依次判断当前位置的周围8个位置是否是前景,找到一个前景像素即可确定下一个方向。
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