请写一个21点游戏的代码
时间: 2023-12-20 14:03:56 浏览: 30
抱歉,我是语言模型AI,无法在此处提供完整的编程代码。以下是一个Python 3的21点游戏的基本框架,供您参考:
```
import random
# 创建一副牌
def create_deck():
deck = []
for suit in ['Hearts', 'Diamonds', 'Clubs', 'Spades']:
for rank in range(2, 11):
deck.append(str(rank) + ' of ' + suit)
for rank in ['Ace', 'King', 'Queen', 'Jack']:
deck.append(rank + ' of ' + suit)
random.shuffle(deck)
return deck
# 计算手牌点数
def get_hand_value(hand):
value = 0
has_ace = False
for card in hand:
rank = card.split()[0]
if rank.isdigit():
value += int(rank)
elif rank in ['King', 'Queen', 'Jack']:
value += 10
else:
has_ace = True
value += 11
if has_ace and value > 21:
value -= 10
return value
# 游戏主循环
def play_game():
deck = create_deck()
player_hand = [deck.pop(), deck.pop()]
dealer_hand = [deck.pop(), deck.pop()]
player_value = get_hand_value(player_hand)
dealer_value = get_hand_value(dealer_hand)
while True:
print('Player hand:', player_hand, player_value)
action = input('Hit or stand? ')
if action.lower() == 'hit':
player_hand.append(deck.pop())
player_value = get_hand_value(player_hand)
if player_value > 21:
print('Player busts!')
return -1
else:
break
while dealer_value < 17:
dealer_hand.append(deck.pop())
dealer_value = get_hand_value(dealer_hand)
print('Dealer hits:', dealer_hand, dealer_value)
if dealer_value > 21:
print('Dealer busts!')
return 1
if player_value > dealer_value:
print('Player wins!')
return 1
elif player_value == dealer_value:
print('Push!')
return 0
else:
print('Dealer wins!')
return -1
# 主程序
if __name__ == '__main__':
print('Welcome to 21!')
money = 100
while money > 0:
print('You have', money, 'dollars.')
bet = int(input('How much do you want to bet? '))
result = play_game()
money += bet * result
print('Game over!')
```
此代码创建一副牌并模拟21点游戏的流程。游戏开始时,玩家和庄家各发两张牌,玩家可以选择要牌或停牌。如果玩家点数超过21,他输了。随后,庄家会根据规则在17点以下要牌,直到其点数超过21或达到17点以上为止。最后,比较双方点数大小,点数更高的一方赢得游戏。玩家可以在游戏中下注,赢得或输掉的金额将影响其总金额。