请写一个21点游戏的c++代码

以下是一个简单的21点游戏的C代码：

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

int main()
{
    int player_total = 0;
    int dealer_total = 0;
    int player_card1, player_card2, dealer_card1, dealer_card2;
    char choice;
    srand(time(NULL)); // 用当前时间作为随机数生成器的种子

    // 发牌
    player_card1 = rand() % 10 + 1;
    player_card2 = rand() % 10 + 1;
    dealer_card1 = rand() % 10 + 1;
    dealer_card2 = rand() % 10 + 1;

    printf("你的牌是：%d 和 %d\n", player_card1, player_card2);
    printf("庄家的牌是：%d 和 ?\n", dealer_card1);

    // 计算点数
    player_total = player_card1 + player_card2;
    dealer_total = dealer_card1;

    // 玩家回合
    do {
        printf("你的总点数是：%d\n", player_total);
        printf("是否要继续要牌？（y/n）\n");
        scanf(" %c", &choice);

        if (choice == 'y') {
            int new_card = rand() % 10 + 1;
            printf("你抽到的牌是：%d\n", new_card);
            player_total += new_card;
        }
    } while (choice == 'y' && player_total <= 21);

    // 庄家回合
    while (dealer_total < 17) {
        int new_card = rand() % 10 + 1;
        printf("庄家抽到的牌是：%d\n", new_card);
        dealer_total += new_card;
    }

    // 结果判断
    printf("你的总点数是：%d，庄家的总点数是：%d\n", player_total, dealer_total);
    if (player_total > 21) {
        printf("你输了！\n");
    } else if (dealer_total > 21) {
        printf("你赢了！\n");
    } else if (player_total > dealer_total) {
        printf("你赢了！\n");
    } else if (player_total < dealer_total) {
        printf("你输了！\n");
    } else {
        printf("平局！\n");
    }

    return 0;
}

该代码使用了随机数生成器来模拟发牌过程，并且使用了循环语句来让玩家和庄家分别进行回合。最后通过比较点数来判断胜负。