层次遍历二叉树算法c语言
时间: 2023-06-17 10:06:34 浏览: 112
二叉树的层次遍历可以使用队列来实现,具体算法如下:
1. 首先将根节点入队。
2. 循环执行以下步骤,直到队列为空:
a. 取出队头元素并输出。
b. 如果该元素有左孩子,则将左孩子入队。
c. 如果该元素有右孩子,则将右孩子入队。
下面是C语言的代码实现:
```c
#include <stdio.h>
#include <stdlib.h>
// 二叉树结点的定义
typedef struct TreeNode {
int val;
struct TreeNode *left;
struct TreeNode *right;
} TreeNode;
// 队列结点的定义
typedef struct QueueNode {
TreeNode *data;
struct QueueNode *next;
} QueueNode;
// 队列的定义
typedef struct Queue {
QueueNode *front;
QueueNode *rear;
} Queue;
// 初始化队列
void initQueue(Queue *q) {
q->front = q->rear = NULL;
}
// 判断队列是否为空
int isEmpty(Queue *q) {
return q->front == NULL;
}
// 入队
void enqueue(Queue *q, TreeNode *data) {
QueueNode *newNode = (QueueNode*)malloc(sizeof(QueueNode));
newNode->data = data;
newNode->next = NULL;
if (isEmpty(q)) {
q->front = q->rear = newNode;
} else {
q->rear->next = newNode;
q->rear = newNode;
}
}
// 出队
TreeNode* dequeue(Queue *q) {
if (isEmpty(q)) {
return NULL;
}
TreeNode *data = q->front->data;
QueueNode *temp = q->front;
if (q->front == q->rear) {
q->front = q->rear = NULL;
} else {
q->front = q->front->next;
}
free(temp);
return data;
}
// 层次遍历二叉树
void levelOrder(TreeNode *root) {
if (root == NULL) {
return;
}
Queue q;
initQueue(&q);
enqueue(&q, root);
while (!isEmpty(&q)) {
TreeNode *node = dequeue(&q);
printf("%d ", node->val);
if (node->left != NULL) {
enqueue(&q, node->left);
}
if (node->right != NULL) {
enqueue(&q, node->right);
}
}
}
// 测试代码
int main() {
// 创建二叉树
TreeNode *root = (TreeNode*)malloc(sizeof(TreeNode));
root->val = 1;
TreeNode *node1 = (TreeNode*)malloc(sizeof(TreeNode));
node1->val = 2;
root->left = node1;
TreeNode *node2 = (TreeNode*)malloc(sizeof(TreeNode));
node2->val = 3;
root->right = node2;
TreeNode *node3 = (TreeNode*)malloc(sizeof(TreeNode));
node3->val = 4;
node1->left = node3;
TreeNode *node4 = (TreeNode*)malloc(sizeof(TreeNode));
node4->val = 5;
node1->right = node4;
TreeNode *node5 = (TreeNode*)malloc(sizeof(TreeNode));
node5->val = 6;
node2->left = node5;
TreeNode *node6 = (TreeNode*)malloc(sizeof(TreeNode));
node6->val = 7;
node2->right = node6;
// 层次遍历二叉树
levelOrder(root);
return 0;
}
```
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