if (Sign == CHAR || Sign == SHORT) adder = pow(2, Bits)/2 ; else adder = 0 ; for(i = 0; i < width ; i++) { /* Convert char data to u8 */ if (i == 0) { if(Sign == UNSIGNEDCHAR || Sign == CHAR) { last_data = (u8)(CharBufferPtr[i] + adder)*data_coe ; curr_data = (u8)(CharBufferPtr[i] + adder)*data_coe ; } else { last_data = (u8)((u16)(ShortBufferPtr[i] + adder)*data_coe) ; curr_data = (u8)((u16)(ShortBufferPtr[i] + adder)*data_coe) ; } } else { if(Sign == UNSIGNEDCHAR || Sign == CHAR) { last_data = (u8)(CharBufferPtr[i-1] + adder)*data_coe ; curr_data = (u8)(CharBufferPtr[i] + adder)*data_coe ; } else { last_data = (u8)((u16)(ShortBufferPtr[i-1] + adder)*data_coe) ; curr_data = (u8)((u16)(ShortBufferPtr[i] + adder)*data_coe) ; } } /* Compare last data value and current data value, draw point between two point */ if (curr_data >= last_data) { for (j = 0 ; j < (curr_data - last_data + 1) ; j++) draw_point(CanvasBufferPtr, i, (height - 1 - curr_data) + j, width, wBlue, wGreen, wRed) ; } else { for (j = 0 ; j < (last_data - curr_data + 1) ; j++) draw_point(CanvasBufferPtr, i, (height - 1 - last_data) + j, width, wBlue, wGreen, wRed) ; } } }

这段代码是一个绘图函数，用于将输入的数据绘制成折线图。函数通过对输入的CharBufferPtr或ShortBufferPtr数组进行处理，将其转化为u8类型的数据，并按照一定的规则绘制到CanvasBufferPtr指向的缓冲区上，从而得到折线图。

函数首先判断输入的数据类型Sign是CHAR还是SHORT，如果是CHAR或SHORT，则在后面的计算中需要对数据进行一定的加减操作。接着，函数对每个数据点进行处理，先将其转化为u8类型的数据，然后与前一个数据点的值进行比较。如果当前数据点的值大于等于前一个数据点的值，则从前一个数据点到当前数据点之间的每个y值上绘制一个点；否则从当前数据点到前一个数据点之间的每个y值上绘制一个点。绘制点的函数是draw_point，其中CanvasBufferPtr是绘图缓冲区指针，i是当前数据点的横坐标，wBlue、wGreen、wRed分别是RGB颜色值，height和width分别是绘图区域的高度和宽度。

相关问题

module DW01_add_tb; // Declare inputs and outputs reg clk; reg [3:0] A; reg [3:0] B; reg CI; wire [3:0] SUM; wire CO; // Instantiate design under test DW01_add dut( .A(A), .B(B), .CI(CI), .SUM(SUM), .CO(CO) ); // Initialize inputs initial begin A = 4'b0000; B = 4'b0000; CI = 0; clk=0; end // Adder test case task test_adder; // Test case 1: 0 + 0 with carry-in of 0 A = 4'b0000; B = 4'b0000; CI = 0; //#10; //if (SUM !== 4'b0000 || CO !== 1'b0) $display("Test failed! 0 + 0 should be 0 with carry-out of 0"); // Test case 2: 7 + 3 with carry-in of 0 A = 4'b0111; B = 4'b0011; CI = 0; //#10; //if (SUM !== 4'b1010 || CO !== 1'b0) $display("Test failed! 7 + 3 should be 10 with carry-out of 0"); // Test case 3: 5 + 11 with carry-in of 1 A = 4'b0101; B = 4'b1011; CI = 1; //#10; //if (SUM !== 4'b0001 || CO !== 1'b1) $display("Test failed! 5 + 11 should be 16 with carry-out of 1"); // Test case 4: 15+15 with carry-in of 1 A = 4'b1111; B = 4'b1111; CI = 1; //#10; //if (SUM !== 4'b1110 || CO !== 1'b1) $display("Overflow!!!"); endtask // Run test cases initial begin test_adder(); $finish; end endmodule // DW01_add_tb this verilog testbench, when compiled by verilator, it reports Verilog $Finish %Warning: vlt/t_xepic_XW01_add: Missing All Finished vlt/t_xepic_XW01_add: %Error:Missing All Finished vlt/t_xepic_XW01_add: FAILED:Missing All Finished it seems there is 1 error in this testbench, so how should I modify this testbench so that it can be compiled by verilator?

To resolve the error reported by Verilator, you need to add a final `end` statement at the end of the testbench after `$finish`. This statement will signal to Verilator that all simulation processes have completed successfully.

Additionally, you need to change the comparison operator in each of the `if` statements from `!==` to `!=`, as Verilator does not support the `!==` operator.

Here's the modified code:

module DW01_add_tb;

// Declare inputs and outputs
reg clk;
reg [3:0] A;
reg [3:0] B;
reg CI;
wire [3:0] SUM;
wire CO;

// Instantiate design under test
DW01_add dut(
  .A(A),
  .B(B),
  .CI(CI),
  .SUM(SUM),
  .CO(CO)
);

// Initialize inputs
initial begin
  A = 4'b0000;
  B = 4'b0000;
  CI = 0;
  clk=0;
end

// Adder test case
task test_adder;
  // Test case 1: 0 + 0 with carry-in of 0
  A = 4'b0000;
  B = 4'b0000;
  CI = 0;
  //#10;
  if (SUM != 4'b0000 || CO != 1'b0)
    $display("Test failed! 0 + 0 should be 0 with carry-out of 0");

  // Test case 2: 7 + 3 with carry-in of 0
  A = 4'b0111;
  B = 4'b0011;
  CI = 0;
  //#10;
  if (SUM != 4'b1010 || CO != 1'b0)
    $display("Test failed! 7 + 3 should be 10 with carry-out of 0");

  // Test case 3: 5 + 11 with carry-in of 1
  A = 4'b0101;
  B = 4'b1011;
  CI = 1;
  //#10;
  if (SUM != 4'b0001 || CO != 1'b1)
    $display("Test failed! 5 + 11 should be 16 with carry-out of 1");

  // Test case 4: 15+15 with carry-in of 1
  A = 4'b1111;
  B = 4'b1111;
  CI = 1;
  //#10;
  if (SUM != 4'b1110 || CO != 1'b1)
    $display("Overflow!!!");

endtask

// Run test cases
initial begin
  test_adder();
  $finish;
end

end // add final end statement

module DW01_add_tb; // Declare inputs and outputs reg [3:0] A; reg [3:0] B; reg CI; wire [3:0] SUM; wire CO; // Instantiate design under test DW01_add dut( .A(A), .B(B), .CI(CI), .SUM(SUM), .CO(CO) ); // Initialize inputs initial begin A = 4'b0000; B = 4'b0000; CI = 0; end // Adder test case task test_adder; // Test case 1: 0 + 0 with carry-in of 0 A = 4'b0000; B = 4'b0000; CI = 0; #10; if (SUM !== 4'b0000 || CO !== 1'b0) $display("Test failed! 0 + 0 should be 0 with carry-out of 0"); // Test case 2: 7 + 3 with carry-in of 0 A = 4'b0111; B = 4'b0011; CI = 0; #10; if (SUM !== 4'b1010 || CO !== 1'b0) $display("Test failed! 7 + 3 should be 10 with carry-out of 0"); // Test case 3: 5 + 11 with carry-in of 1 A = 4'b0101; B = 4'b1011; CI = 1; #10; if (SUM !== 4'b0001 || CO !== 1'b1) $display("Test failed! 5 + 11 should be 16 with carry-out of 1"); // Test case 4: 15+15 with carry-in of 1 A = 4'b1111; B = 4'b1111; CI = 1; #10; if (SUM !== 4'b1110 || CO !== 1'b1) $display("Overflow!!!"); endtask // Run test cases initial begin test_adder(); $finish; end endmodule // DW01_add_tb If I want to replace the delays, i.e, #10; in this piece of verilog code, by below code: integer cyc; initial cyc=1; always @ (posedge clk) begin cyc <= cyc+1; if(cyc==1)begin in_val1 <=4'd4; end else if (cyc==2) begin if (out_val1 !==8'b1) $stop; in_val <=4'd3; end else if (cyc==3)begin if(out_val1 !== 8'b10)$stop; in_val1 <= 4'd7; end else if(cyc==4) begin $write("ALL Finished \n"); $finish; end end in other words, using pound delay # is not allowed, how should I modify the code?

To replace the delays with the code you provided, you can use a counter to keep track of the number of clock cycles and use an if-else statement to control the input values at each cycle. Here's an example:

module DW01_add_tb;

  // Declare inputs and outputs
  reg [3:0] in_val1;
  reg [3:0] in_val2;
  wire [3:0] out_sum;
  wire out_carry;

  // Instantiate design under test
  DW01_add dut(
    .A(in_val1),
    .B(in_val2),
    .SUM(out_sum),
    .CO(out_carry)
  );

  // Initialize inputs
  initial begin
    in_val1 = 4'b0000;
    in_val2 = 4'b0000;
  end

  // Clock generator
  reg clk = 0;
  always #5 clk = ~clk;

  // Counter to keep track of clock cycles
  integer cyc = 0;

  // Control input values without using pound delay #
  always @(posedge clk) begin
    cyc <= cyc + 1;
    if (cyc == 1) begin
      in_val1 <= 4'd4;
    end else if (cyc == 2) begin
      if (out_sum !== 4'b0001 || out_carry !== 1'b0) $stop;
      in_val1 <= 4'd3;
    end else if (cyc == 3) begin
      if (out_sum !== 4'b0111 || out_carry !== 1'b0) $stop;
      in_val1 <= 4'd7;
      in_val2 <= 4'd5;
    end else if (cyc == 4) begin
      if (out_sum !== 4'b0000 || out_carry !== 1'b1) $stop;
      in_val1 <= 4'd15;
      in_val2 <= 4'd15;
    end else if (cyc == 5) begin
      if (out_sum !== 4'b1110 || out_carry !== 1'b1) $stop;
      $write("ALL Finished\n");
      $finish;
    end
  end

endmodule // DW01_add_tb

In this code, the clock generator generates a clock signal with a period of 10 time units (5 time units high, 5 time units low). The counter `cyc` keeps track of the number of clock cycles and is incremented on each positive edge of the clock. The if-else statement controls the input values at each clock cycle based on the value of `cyc`, and the output values are checked using an assertion. Finally, when all the test cases are completed, the simulation is finished using `$finish`.