用python写一个遍历文件夹内的文件，如果发现缺失文件，就复制前后文件并重命名保存到文件中的脚本。

好的，以下是Python代码实现：

import os
import shutil

# 遍历文件夹内的文件
def traverse_files(directory):
    for root, dirs, files in os.walk(directory):
        for file in files:
            yield os.path.join(root, file)

# 处理文件缺失的情况
def handle_missing_file(filename):
    try:
        with open(filename, "r") as f:
            pass
    except FileNotFoundError:
        prev_file = ""
        next_file = ""
        for file in traverse_files(os.path.dirname(filename)):
            if file > filename:
                next_file = file
                break
            prev_file = file
        if prev_file and next_file:
            new_file = os.path.join(os.path.dirname(filename), os.path.basename(prev_file).split(".")[0] + "_" + os.path.basename(next_file))
            shutil.copy(prev_file, new_file)
            print("File copied and renamed as ", new_file)

# 传入文件夹路径
directory_path = "path/to/directory"
for file in traverse_files(directory_path):
    handle_missing_file(file)

希望对您有所帮助！请问还有其它问题吗？