稀疏矩阵的快速转置代码
时间: 2023-08-06 21:20:26 浏览: 88
以下是稀疏矩阵快速转置的Python代码实现:
```python
def sparse_matrix_transpose(matrix):
"""
:param matrix: 稀疏矩阵
:return: 转置后的稀疏矩阵
"""
# 获取矩阵的行、列、非零元素个数
rows, cols, vals = matrix[0], matrix[1], matrix[2]
n = len(rows)
# 统计每一列的非零元素个数
col_counts = [0] * cols
for i in range(n):
col_counts[rows[i]] += 1
# 计算每一列的起始位置
col_starts = [0] * (cols + 1)
col_starts[0] = 0
for i in range(1, cols + 1):
col_starts[i] = col_starts[i - 1] + col_counts[i - 1]
# 创建新的稀疏矩阵
new_rows = [0] * n
new_cols = [0] * n
new_vals = [0] * n
for i in range(n):
col = rows[i]
start = col_starts[col]
new_rows[start] = cols[i]
new_cols[start] = rows[i]
new_vals[start] = vals[i]
col_starts[col] += 1
# 返回转置后的稀疏矩阵
return [cols, rows, vals]
```
该代码实现的思路是先统计每一列的非零元素个数,然后计算每一列的起始位置,最后创建新的稀疏矩阵。
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