设计一个2048小游戏软件,采用键盘操作,w对应上移,a对应左移,s对应下移,d对应右移。(不要使用pygame) 基本功能:初始在随机位置显示1个数字“2”,状态栏显示当前操作次数;能实现游戏逻辑。 发挥功能:界面的美化、历史记录等不限。请写出python代码
时间: 2024-03-06 16:49:44 浏览: 132
好的,以下是一个简单的Python代码实现,实现了2048小游戏的基本功能:
```python
import random
import copy
import os
# 初始化游戏界面
board = [[0 for i in range(4)] for j in range(4)]
score = 0
step = 0
# 在随机位置生成数字2
def generate_num():
empty_pos = []
for i in range(4):
for j in range(4):
if board[i][j] == 0:
empty_pos.append((i, j))
if empty_pos:
pos = random.choice(empty_pos)
board[pos[0]][pos[1]] = 2
# 判断游戏是否结束
def is_game_over():
for i in range(4):
for j in range(4):
if board[i][j] == 0:
return False
if j < 3 and board[i][j] == board[i][j+1]:
return False
if i < 3 and board[i][j] == board[i+1][j]:
return False
return True
# 合并相邻的相同数字
def merge():
global board, score
new_board = copy.deepcopy(board)
for i in range(4):
j = 0
while j < 3:
if new_board[i][j] == new_board[i][j+1]:
new_board[i][j] *= 2
score += new_board[i][j]
new_board[i][j+1] = 0
j += 1
board = new_board
# 移动数字
def move(direction):
global board, step
if direction == 'w':
board = [[board[j][i] for j in range(4)] for i in range(4)]
merge()
board = [[board[j][i] for j in range(4)] for i in range(4)]
step += 1
elif direction == 'a':
merge()
step += 1
elif direction == 's':
board = [[board[j][i] for j in range(4)] for i in range(4)]
board.reverse()
merge()
board.reverse()
board = [[board[j][i] for j in range(4)] for i in range(4)]
step += 1
elif direction == 'd':
board.reverse()
merge()
board.reverse()
step += 1
# 显示游戏界面
def show_board():
os.system('cls')
print('Score:', score, 'Step:', step)
for i in range(4):
for j in range(4):
print(board[i][j], end='\t')
print()
# 游戏主循环
while True:
generate_num()
show_board()
if is_game_over():
print('Game over!')
break
direction = input('Please input direction(w/a/s/d):')
move(direction)
```
以上代码实现了基本功能,可以在终端中运行。界面比较简陋,可以使用tkinter库等来实现美化。同时,可以使用文件读写来实现历史记录等功能。
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