java将员工按照工资由低到高（工资一样则按年龄由小到大）排序，显示名字代码

可以使用Java中的Collections.sort()方法来实现员工按照工资排序，如果工资相同则按照年龄排序。具体代码如下：

import java.util.*;

class Employee implements Comparable<Employee> {
    private String name;
    private int age;
    private int salary;

    public Employee(String name, int age, int salary) {
        this.name = name;
        this.age = age;
        this.salary = salary;
    }

    public String getName() {
        return name;
    }

    public int getAge() {
        return age;
    }

    public int getSalary() {
        return salary;
    }

    @Override
    public int compareTo(Employee emp) {
        if (this.salary != emp.salary) {
            return this.salary - emp.salary;
        } else {
            return this.age - emp.age;
        }
    }
}

public class Main {
    public static void main(String[] args) {
        List<Employee> employeeList = new ArrayList<>();
        employeeList.add(new Employee("Tom", 22, 2500));
        employeeList.add(new Employee("Jerry", 25, 3000));
        employeeList.add(new Employee("Mike", 22, 2000));

        Collections.sort(employeeList);

        for (Employee emp : employeeList) {
            System.out.println(emp.getName() + ", salary: " + emp.getSalary());
        }
    }
}

输出结果为:

Mike, salary: 2000
Tom, salary: 2500
Jerry, salary: 3000