用c++编程设abcd*e=dcba（a非0，e非0非1），求满足条件的abcd和e

#include <stdio.h>

int main() {
    int a, b, c, d, e;
    for (a = 1; a <= 9; a++) {
        for (b = 0; b <= 9; b++) {
            for (c = 0; c <= 9; c++) {
                for (d = 0; d <= 9; d++) {
                    for (e = 2; e <= 9; e++) {
                        if (a * 1000 + b * 100 + c * 10 + d
                            == d * 1000 + c * 100 + b * 10 + a
                            && a * e == d * 10 + c) {
                            printf("%d%d%d%d*%d=%d%d%d%d\n", a, b, c, d, e, d, c, b, a);
                        }
                    }
                }
            }
        }
    }
    return 0;
}