/** * Shifts rows between startRow and endRow n number of rows. * If you use a negative number, it will shift rows up. * Code ensures that rows don't wrap around. * * Calls shiftRows(startRow, endRow, n, false, false); * * <p> * Additionally shifts merged regions that are completely defined in these * rows (ie. merged 2 cells on a row to be shifted). * @param startRow the row to start shifting * @param endRow the row to end shifting * @param n the number of rows to shift */

这是一个函数的注释说明。该函数的作用是将从 startRow 到 endRow 的所有行向下移动 n 行，如果 n 为负数，则将行向上移动。该函数确保行不会超出范围。此外，该函数还会移动那些完全定义在这些行中的合并区域（例如，在要移动的行上合并了两个单元格）。具体实现可能需要考虑边界情况和数据类型等细节。

相关问题

帮我写出以下java代码：The clearInvisibles method takes as argument the width w and the height h of the window, and deletes from the arraylist of bubbles any bubble which is not visible in the window anymore. For each bubble which is deleted, the score decreases by 1. WARNING: when you use the remove method of Java’s ArrayList class to remove an element of an arraylist at index i, the arraylist immediately shifts down by one position all the elements with higher indexes to make the arraylist one element shorter. So, for example, when removing the element at index i, the element at index i+1 immediately moves to the position at index i, the element at index i+2 immediately moves to the position at index i+1, etc. This means that on the next iteration of the loop, when i has become i+1, the element that you will be testing at index i+1 is in fact the element that used to be at index i+2. Which means that the element that used to be at index i+1 (and which is now at index i) will never be tested! Therefore, when removing elements from an arraylist, if your loop starts at index 0 and goes up the indexes in the arraylist, then your loop will fail to test some elements! CONCLUSION: when removing elements from an arraylist, your loop must start from the END of the arraylist and go DOWN to index 0. The deleteBubblesAtPoint method takes as argument the coordinates (x, y) of a point, and deletes from the arraylist of bubbles any bubble which contains this point (multiple bubbles might contain the point, because bubbles can overlap in the window). For each bubble which is deleted, the score increases by 1. The drawAll method draws all the bubbles in the arraylist of bubbles. Make sure you test as many methods of the Model class as poss

public class Model {
private ArrayList<Bubble> bubbles;
private int score;

public void clearInvisibles(int w, int h) {
for (int i = bubbles.size() - 1; i >= 0; i--) {
Bubble bubble = bubbles.get(i);
if (!bubble.isVisible(w, h)) {
bubbles.remove(i);
score--;
}
}
}

public void deleteBubblesAtPoint(int x, int y) {
Iterator<Bubble> iterator = bubbles.iterator();
while (iterator.hasNext()) {
Bubble bubble = iterator.next();
if (bubble.containsPoint(x, y)) {
iterator.remove();
score++;
}
}
}

public void drawAll() {
for (Bubble bubble : bubbles) {
bubble.draw();
}
}
}

class Bubble {
private int x;
private int y;
private int radius;

public boolean isVisible(int w, int h) {
return (x + radius >= 0 && x - radius <= w && y + radius >= 0 && y - radius <= h);
}

public boolean containsPoint(int x, int y) {
return (Math.pow((this.x - x), 2) + Math.pow((this.y - y), 2) <= Math.pow(radius, 2));
}

public void draw() {
// code to draw bubble
}
}

3）On the basis of question 2, rewrite the C program to shift the sequence to the right by n bits. Sequence input, sequence output and sequence right shift are realized by three sub functions respectively. (The number of series and the number of bits shifted to the right are entered by the user from the keyboard) For example： Enter the length of the sequence：6 Input original sequence：1 2 3 4 5 6 Enter the number of digits shifted to the right：3 After the cycle shifts 3 bits to the right, it becomes： 4 5 6 1 2 3

Sure, I can help you with that! Here's the modified C program:

#include <stdio.h>

// Function to read the sequence from the user
void readSequence(int sequence[], int length) {
    printf("Input original sequence:");
    for (int i = 0; i < length; i++) {
        scanf("%d", &sequence[i]);
    }
}

// Function to print the shifted sequence
void printSequence(int sequence[], int length) {
    printf("After the cycle shifts %d bits to the right, it becomes:", length);
    for (int i = 0; i < length; i++) {
        printf(" %d", sequence[i]);
    }
    printf("\n");
}

// Function to shift the sequence to the right by n bits
void shiftSequence(int sequence[], int length, int n) {
    int temp;
    for (int i = 0; i < n; i++) {
        // Store the last element of the sequence in a temporary variable
        temp = sequence[length - 1];
        // Shift all elements to the right by one position
        for (int j = length - 1; j > 0; j--) {
            sequence[j] = sequence[j - 1];
        }
        // Place the last element at the beginning of the sequence
        sequence[0] = temp;
    }
}

int main() {
    int length, n;
    printf("Enter the length of the sequence:");
    scanf("%d", &length);
    int sequence[length];
    readSequence(sequence, length);
    printf("Enter the number of digits shifted to the right:");
    scanf("%d", &n);
    shiftSequence(sequence, length, n);
    printSequence(sequence, length);
    return 0;
}

I hope this helps! Let me know if you have any questions.