/** * Shifts rows between startRow and endRow n number of rows. * If you use a negative number, it will shift rows up. * Code ensures that rows don't wrap around. * * Calls shiftRows(startRow, endRow, n, false, false); * * <p> * Additionally shifts merged regions that are completely defined in these * rows (ie. merged 2 cells on a row to be shifted). * @param startRow the row to start shifting * @param endRow the row to end shifting * @param n the number of rows to shift */

时间: 2024-02-17 17:03:19 浏览: 15
这是一个函数的注释说明。该函数的作用是将从 startRow 到 endRow 的所有行向下移动 n 行,如果 n 为负数,则将行向上移动。该函数确保行不会超出范围。此外,该函数还会移动那些完全定义在这些行中的合并区域(例如,在要移动的行上合并了两个单元格)。具体实现可能需要考虑边界情况和数据类型等细节。
相关问题

*(unsigned int*)0x40010C00 =((1)<<(4*0))

This line of code is setting a specific bit in a register at memory address 0x40010C00. The expression `((1)<<(4*0))` shifts the value 1 by 0 bits, which effectively leaves the value unchanged (since any number shifted by 0 bits is still the same number). The result is simply 1. The outer parentheses are not strictly necessary, but they help clarify the order of operations. The entire expression is then cast to an `unsigned int*`, which is a pointer to an unsigned integer. This pointer is then dereferenced and assigned the value of 1, effectively setting a specific bit in the register to 1. The exact meaning of this operation depends on the specific hardware and register being accessed.

Verilog HDL语言实现16*16LED点阵滚动显示英文”red“的程序

下面是一个Verilog HDL程序,用于实现16x16 LED点阵的滚动显示英文单词“red”。该程序使用了一个FPGA板上的16位计数器和一个ROM存储器,其中存储了“red”单词的字模信息。每当计数器增加到特定值时,它将触发一个时钟信号,该信号用于读取ROM存储器并将相应的LED点亮。 ```verilog module led_matrix( input clk, input rst, output reg [15:0] led_row, output reg [15:0] led_col); reg [3:0] row_counter; reg [15:0] col_counter; reg [7:0] rom_data; parameter delay = 500000; //delay cycles between column shifts //ROM memory containing "red" word pattern //each byte represents a column of 8 LEDs //MSB of each byte represents the top LED in the column //LSB of each byte represents the bottom LED in the column //16 bytes in total for 16x16 LED matrix //pattern for "r" reg [7:0] rom_r[16] = { 8'b00000010, 8'b00000010, 8'b00000100, 8'b00001000, 8'b00001000, 8'b00001110, 8'b00001010, 8'b00001010, 8'b00000000, 8'b00000000, 8'b00000000, 8'b00000000, 8'b00000000, 8'b00000000, 8'b00000000, 8'b00000000 }; //pattern for "e" reg [7:0] rom_e[16] = { 8'b00000000, 8'b00000000, 8'b00111100, 8'b01000010, 8'b01000000, 8'b01111000, 8'b01000000, 8'b01000010, 8'b00111100, 8'b00000000, 8'b00000000, 8'b00000000, 8'b00000000, 8'b00000000, 8'b00000000, 8'b00000000 }; //pattern for "d" reg [7:0] rom_d[16] = { 8'b00000000, 8'b00000000, 8'b00011100, 8'b00100010, 8'b00100010, 8'b00100010, 8'b00100010, 8'b00100010, 8'b00011100, 8'b00000000, 8'b00000000, 8'b00000000, 8'b00000000, 8'b00000000, 8'b00000000, 8'b00000000 }; always @(posedge clk) begin if (rst) begin row_counter <= 4'd0; col_counter <= 16'd0; led_row <= 16'd0; led_col <= 16'd0; end else begin if (col_counter >= delay) begin col_counter <= 16'd0; case (row_counter) 4'd0: rom_data <= rom_r[col_counter]; 4'd1: rom_data <= rom_e[col_counter]; 4'd2: rom_data <= rom_d[col_counter]; default: rom_data <= 8'b0; endcase led_col <= {led_col[14:0], led_row[15]}; led_row <= {led_row[14:0], rom_data}; if (row_counter == 4'd15) begin row_counter <= 4'd0; end else begin row_counter <= row_counter + 4'd1; end end else begin col_counter <= col_counter + 1; end end end endmodule ``` 在这个程序中,LED点阵被表示为16x16的矩阵,其中每个元素都是一个LED。程序使用两个16位寄存器来控制LED点阵的输出:led_row和led_col。led_col寄存器用于存储点阵中的列,而led_row寄存器用于存储点阵中的行。 程序使用一个4位计数器来控制行的输出。当计数器增加到15时,它将被重置为0。程序还使用一个16位计数器来控制列的输出。每当计数器增加到特定值(delay)时,它将重置为0,并从ROM存储器中读取相应的字模信息。该程序使用了三个ROM存储器,分别存储字母“r”、“e”和“d”的字模信息。这些字模信息在ROM存储器中以每列8个LED的形式存储,总共有16列,因此需要16个字节来存储每个字母的字模信息。程序通过case语句来选择要读取哪个字母的字模信息,并将该信息存储到rom_data寄存器中。然后,程序使用led_col寄存器将该列左移一位,并使用led_row寄存器将rom_data信息向上移动一行,并将最后一行设置为相应的LED点亮。这样,程序就能够实现16x16 LED点阵的滚动显示英文单词“red”。

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帮我写出以下java代码:The clearInvisibles method takes as argument the width w and the height h of the window, and deletes from the arraylist of bubbles any bubble which is not visible in the window anymore. For each bubble which is deleted, the score decreases by 1. WARNING: when you use the remove method of Java’s ArrayList class to remove an element of an arraylist at index i, the arraylist immediately shifts down by one position all the elements with higher indexes to make the arraylist one element shorter. So, for example, when removing the element at index i, the element at index i+1 immediately moves to the position at index i, the element at index i+2 immediately moves to the position at index i+1, etc. This means that on the next iteration of the loop, when i has become i+1, the element that you will be testing at index i+1 is in fact the element that used to be at index i+2. Which means that the element that used to be at index i+1 (and which is now at index i) will never be tested! Therefore, when removing elements from an arraylist, if your loop starts at index 0 and goes up the indexes in the arraylist, then your loop will fail to test some elements! CONCLUSION: when removing elements from an arraylist, your loop must start from the END of the arraylist and go DOWN to index 0. The deleteBubblesAtPoint method takes as argument the coordinates (x, y) of a point, and deletes from the arraylist of bubbles any bubble which contains this point (multiple bubbles might contain the point, because bubbles can overlap in the window). For each bubble which is deleted, the score increases by 1. The drawAll method draws all the bubbles in the arraylist of bubbles. Make sure you test as many methods of the Model class as poss

Shifts in China’s Rural and Urban Population: 2000-2020 The bar chart clearly reveals that from 2000 to 2020, while the total population in China increased moderately from 1.25 billion to 1.41 billion, population in urban and rural areas experienced dramatic shifts in different directions. Urban population rose from 450 million in 2000 to 670 million in 2010 and 900 million in 2020; contrastingly, rural population declined from 800 million in 2000 to 680 million in 2010 and 510 million in 2020. The population gap narrowed largely because of the joint effects of urbanization, unequal economic opportunities in rural and urban areas, and the expansion of higher education. In the first place, there was a large-scale urban sprawl during this period. Places which had been part of the vast countryside were incorporated into cities, causing hundreds of millions of rural dwellers to be passively transformed into urban residents. What’s more, while urban living standards improved greatly in these years, few economic opportunities fell on rural areas and most peasant families remained at the poverty line. Poverty prompted the call for change, leading a large quantity of healthy young peasants to leave their hometowns and flock to cities for a better living. Last but not least, China’s higher education grew at an unprecedented rate in these years. More high school graduates than ever before entered colleges and universities, most of whom preferred to stay in urban areas after graduation for personal development. The increase in urban population was a sure indication of economic and educational achievements in China. It benefited the country in many aspects, relieving the shortage of labor force in cities, lessening the burden of peasants to support their families, and affording young people from rural areas more opportunities to display their talents. However, the migration of rural residents into urban areas inevitably brought about disadvantages. Some of them, such as waste of arable land and left-behind children in the countryside, as well as traffic congestion and soaring housing prices in cities, have already called the attention of the government and corresponding measures have begun to take effect. But others, especially the inability of many peasants to integrate into urban life due to their lack of education and civilized habits, have long been neglected. In this sense, we cannot be satisfied with the superficially optimistic figures in the chart, but should endeavor to foster the integration of these newcomers by providing them with adequate assistance in educational and cultural aspects, so that they can find easier access to the prosperity and convenience of urban life and be more fully devoted to the development of cities.翻译成英文版两百单词左右的文章

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