Sum = 0 for i in range(1,11): for j in range(1,i+1): m = 1 m*=j Sum+=m print(Sum)代码解释
时间: 2024-05-30 19:11:13 浏览: 17
这个代码实现了计算1!+2!+3!+...+10!的结果。
具体解释如下:
首先,初始化变量Sum为0。
接着,使用 for 循环遍历1到10这10个数字,循环变量为i。
在每次循环中,使用另一个 for 循环遍历1到i这些数字,循环变量为j。
在内层循环中,将变量m初始化为1,然后将j乘到m上。
最后,将m加到Sum上。
当外层循环结束时,Sum中存储的就是1!+2!+3!+...+10!的结果。
因此,最后输出Sum即可。
相关问题
sum = 0 for i in range(1, 11): sum += i print(sum)
This code will output the value of the variable "sum" after each iteration of the for loop.
The output will be:
1
2
3
4
5
6
7
8
9
10
This is because the variable "sum" is being assigned the value of "i" in each iteration of the loop, and then the current value of "sum" is printed. Since "i" is incrementing from 1 to 10, the output will be the numbers 1 through 10 printed on separate lines.
Note that the initial value of "sum" is 0, but it is immediately overwritten in the first iteration of the loop. If the intention was to add up the values of "i" from 1 to 10, the code should be modified as follows:
sum = 0
for i in range(1, 11):
sum += i
print(sum)
This would output the value of the variable "sum" after the loop has completed, which would be the sum of the numbers from 1 to 10 (i.e. 55).
sum=0 for i in range(1,11): sum += i print( sum)
您的代码中,变量sum是初始值为0的累加器,但是在每次循环中,您将i直接赋值给了sum,而没有将i加入到sum中。因此,每次循环结束后,sum的值都将等于i的值。建议您将代码修改为以下形式:
sum = 0
for i in range(1, 11):
sum += i
print(sum)
这样,每次循环中都将i加入到sum中,循环结束后,sum的值就是1到10的和,即55。
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