for i in range(1000000000): sum += 1，为什么i是1到11

这是因为您的代码中，没有对变量 `sum` 进行初始化，而在 Python 中，未初始化的变量默认值为 0。因此，在执行 `sum += 1` 时，实际上是将 `sum` 的值加 1，而 `sum` 的初始值为 0，所以最终结果是 1。而 `range(1000000000)` 会生成一个从 0 到 999999999 的整数序列，所以当 `i` 的值增加到 11 时，`sum` 的值已经变成了 11。

相关问题

sum = 0 for i in range(1, 11): sum += i print(sum)

This code will output the value of the variable "sum" after each iteration of the for loop.

The output will be:

1
2
3
4
5
6
7
8
9
10

This is because the variable "sum" is being assigned the value of "i" in each iteration of the loop, and then the current value of "sum" is printed. Since "i" is incrementing from 1 to 10, the output will be the numbers 1 through 10 printed on separate lines.

Note that the initial value of "sum" is 0, but it is immediately overwritten in the first iteration of the loop. If the intention was to add up the values of "i" from 1 to 10, the code should be modified as follows:

sum = 0
for i in range(1, 11):
sum += i
print(sum)

This would output the value of the variable "sum" after the loop has completed, which would be the sum of the numbers from 1 to 10 (i.e. 55).

sum=0 for i in range(1,11): sum += i print( sum)

您的代码中，变量sum是初始值为0的累加器，但是在每次循环中，您将i直接赋值给了sum，而没有将i加入到sum中。因此，每次循环结束后，sum的值都将等于i的值。建议您将代码修改为以下形式：

sum = 0
for i in range(1, 11):
sum += i
print(sum)

这样，每次循环中都将i加入到sum中，循环结束后，sum的值就是1到10的和，即55。