请用C语言写一个15*15的扫雷小游戏

扫雷是一个非常有趣的游戏，可以使用 C 语言编写。下面是一个简单的扫雷代码示例：

#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#define ROW 15
#define COL 15
#define MINE_COUNT 99
int map[ROW][COL];
int state[ROW][COL];
void init() {
    int i, j;
    int x, y;
    int count;
    srand(time(0));
    for (i = 0; i < MINE_COUNT; i++) {
        x = rand() % ROW;
        y = rand() % COL;
        if (map[x][y] == -1) {
            i--;
            continue;
        }
        map[x][y] = -1;
        for (j = -1; j <= 1; j++) {
            for (k = -1; k <= 1; k++) {
                if (x + j >= 0 && x + j < ROW && y + k >= 0 && y + k < COL && map[x + j][y + k] != -1) {
                    map[x + j][y + k]++;
                }
            }
        }
    }
}
void show() {
    int i, j;
    printf("  ");
    for (i = 0; i < COL; i++) {
        printf("%d ", i);
    }
    printf("\n");
    for (i = 0; i < ROW; i++) {
        printf("%2d ", i);
        for (j = 0; j < COL; j++) {
            if (state[i][j] == 1) {
                printf("%d ", map[i][j]);
            } else {
                printf("* ");
            }
        }
        printf("\n");
    }
}
void open(int x, int y) {
    if (x < 0 || x >= ROW || y < 0 || y >= COL) {
        return;
    }
    if (state[x][y] == 1) {
        return;
    }
    if (map[x][y] == -1) {
        printf("you lose\n");
        exit(0);
    }
    state[x][y] = 1;
    if (map[x][y] == 0) {
        open(x - 1, y - 1);
        open(x - 1, y);
        open(x - 1, y + 1);
        open(x, y - 1);
        open(x, y + 1);
        open(x + 1, y - 1);
        open(x + 1, y);
        open(x + 1, y + 1);
    }
}
int main() {
    int x, y;
    init();
    while (1) {
        show();
        printf("input x y:");