用python制作一个贪吃蛇小游戏

好的，以下是一个简单的贪吃蛇小游戏的 Python 代码：

import pygame
import random

# 初始化 Pygame
pygame.init()

# 游戏窗口大小
WINDOW_WIDTH = 640
WINDOW_HEIGHT = 480

# 颜色定义
BLACK = (0, 0, 0)
WHITE = (255, 255, 255)
GREEN = (0, 255, 0)
RED = (255, 0, 0)

# 创建游戏窗口
window = pygame.display.set_mode((WINDOW_WIDTH, WINDOW_HEIGHT))
pygame.display.set_caption('贪吃蛇')

# 设置游戏时钟
clock = pygame.time.Clock()

# 蛇的初始位置和长度
snake_x = 100
snake_y = 100
snake_length = 1
snake_body = [(snake_x, snake_y)]

# 食物的初始位置
food_x = random.randint(0, WINDOW_WIDTH - 10)
food_y = random.randint(0, WINDOW_HEIGHT - 10)

# 游戏循环
while True:
    # 处理事件
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            pygame.quit()
            exit()

    # 处理键盘输入
    keys = pygame.key.get_pressed()
    if keys[pygame.K_LEFT]:
        snake_x -= 10
    elif keys[pygame.K_RIGHT]:
        snake_x += 10
    elif keys[pygame.K_UP]:
        snake_y -= 10
    elif keys[pygame.K_DOWN]:
        snake_y += 10

    # 判断是否吃到食物
    if snake_x == food_x and snake_y == food_y:
        snake_length += 1
        food_x = random.randint(0, WINDOW_WIDTH - 10)
        food_y = random.randint(0, WINDOW_HEIGHT - 10)

    # 更新蛇的身体
    snake_body.insert(0, (snake_x, snake_y))
    if len(snake_body) > snake_length:
        snake_body.pop()

    # 绘制游戏界面
    window.fill(BLACK)
    pygame.draw.rect(window, GREEN, (food_x, food_y, 10, 10))
    for x, y in snake_body:
        pygame.draw.rect(window, WHITE, (x, y, 10, 10))
    pygame.display.update()

    # 控制游戏帧率
    clock.tick(30)

希望这个代码能够帮到你！