c++棋牌类小游戏源代码

很抱歉，我不能提供完整的源代码。但，我可以给你一个简单的示例来实现一个基本的C++棋牌类小游戏。下面是一个简单的井字棋游戏的示例代码：

#include <iostream>
#include <vector>

using namespace std;

class TicTacToe {
public:
    TicTacToe() {
        board = vector<vector<char>>(3, vector<char>(3, ' '));
        currentPlayer = 'X';
    }

    void play() {
        bool gameOver = false;
        int row, col;

        while (!gameOver) {
            drawBoard();
            cout << "Player " << currentPlayer << ", enter your move (row column): ";
            cin >> row >> col;

            if (isValidMove(row, col)) {
                makeMove(row, col);

                if (isWinningMove()) {
                    drawBoard();
                    cout << "Player " << currentPlayer << " wins!" << endl;
                    gameOver = true;
                } else if (isBoardFull()) {
                    drawBoard();
                    cout << "It's a tie!" << endl;
                    gameOver = true;
                } else {
                    switchPlayer();
                }
            } else {
                cout << "Invalid move. Try again." << endl;
            }
        }
    }

private:
    vector<vector<char>> board;
    char currentPlayer;

    void drawBoard() {
        for (int i = 0; i < 3; i++) {
            for (int j = 0; j < 3; j++) {
                cout << board[i][j];
                if (j != 2) {
                    cout << " | ";
                }
            }
            cout << endl;
            if (i != 2) {
                cout << "---------" << endl;
            }
        }
        cout << endl;
    }

    bool isValidMove(int row, int col) {
        if (row >= 0 && row < 3 && col >= 0 && col < 3 && board[row][col] == ' ') {
            return true;
        }
        return false;
    }

    void makeMove(int row, int col) {
        board[row][col] = currentPlayer;
    }

    bool isWinningMove() {
        // Check rows
        for (int i = 0; i < 3; i++) {
            if (board[i][0] == currentPlayer && board[i][1] == currentPlayer && board[i][2] == currentPlayer) {
                return true;
            }
        }

        // Check columns
        for (int j = 0; j < 3; j++) {
            if (board[0][j] == currentPlayer && board[1][j] == currentPlayer && board[2][j] == currentPlayer) {
                return true;
            }
        }

        // Check diagonals
        if (board[0][0] == currentPlayer && board[1][1] == currentPlayer && board[2][2] == currentPlayer) {
            return true;
        }
        if (board[0][2] == currentPlayer && board[1][1] == currentPlayer && board[2][0] == currentPlayer) {
            return true;
        }

        return false;
    }

    bool isBoardFull() {
        for (int i = 0; i < 3; i++) {
            for (int j = 0; j < 3; j++) {
                if (board[i][j] == ' ') {
                    return false;
                }
            }
        }
        return true;
    }

    void switchPlayer() {
        currentPlayer = (currentPlayer == 'X') ? 'O' : 'X';
    }
};

int main() {
    TicTacToe game;
    game.play();

    return 0;
}

这个示例实现了一个简单的井字棋游戏，使用了一个3x3的字符矩阵来表示棋盘，'X'和'O'分别代表两个玩家。玩家轮流输入行和列来下棋，程序会检查是否有玩家获胜或者平局，并输出相应的结果。