用CCS写一个数字时钟
时间: 2023-03-26 22:03:36 浏览: 98
你好,我可以回答这个问题。使用 CCS 编写数字时钟的代码如下:
```c
#include <msp430.h>
#define LED1 BIT
#define LED2 BIT6
#define LED3 BIT1
#define LED4 BIT5
#define LED5 BIT7
#define LED6 BIT2
#define LED7 BIT4
#define LED8 BIT3
void delay(void)
{
volatile unsigned int i;
for (i = ; i < 20000; i++);
}
void display(int num)
{
switch (num) {
case :
P1OUT = LED1 | LED2 | LED3 | LED5 | LED6 | LED7;
break;
case 1:
P1OUT = LED3 | LED5;
break;
case 2:
P1OUT = LED1 | LED3 | LED4 | LED6 | LED7;
break;
case 3:
P1OUT = LED1 | LED3 | LED4 | LED5 | LED7;
break;
case 4:
P1OUT = LED2 | LED3 | LED4 | LED5;
break;
case 5:
P1OUT = LED1 | LED2 | LED4 | LED5 | LED7;
break;
case 6:
P1OUT = LED1 | LED2 | LED4 | LED5 | LED6 | LED7;
break;
case 7:
P1OUT = LED1 | LED3 | LED5;
break;
case 8:
P1OUT = LED1 | LED2 | LED3 | LED4 | LED5 | LED6 | LED7;
break;
case 9:
P1OUT = LED1 | LED2 | LED3 | LED4 | LED5 | LED7;
break;
default:
break;
}
}
void main(void)
{
WDTCTL = WDTPW + WDTHOLD;
P1DIR |= LED1 | LED2 | LED3 | LED4 | LED5 | LED6 | LED7 | LED8;
P1OUT &= ~(LED1 | LED2 | LED3 | LED4 | LED5 | LED6 | LED7 | LED8);
while (1) {
int hour, minute, second;
for (hour = ; hour < 24; hour++) {
for (minute = ; minute < 60; minute++) {
for (second = ; second < 60; second++) {
display(hour / 10);
P1OUT |= LED8;
delay();
P1OUT &= ~LED8;
display(hour % 10);
P1OUT |= LED7;
delay();
P1OUT &= ~LED7;
display(minute / 10);
P1OUT |= LED6;
delay();
P1OUT &= ~LED6;
display(minute % 10);
P1OUT |= LED5;
delay();
P1OUT &= ~LED5;
display(second / 10);
P1OUT |= LED4;
delay();
P1OUT &= ~LED4;
display(second % 10);
P1OUT |= LED3;
delay();
P1OUT &= ~LED3;
}
}
}
}
}
```
这个代码使用 MSP430 微控制器控制 8 个 LED 灯,实现了一个数字时钟。时钟会不断循环显示当前的时间,每个数字都会持续显示 1 秒钟。