python随机生成两个3*4的整数矩阵,计算两个矩阵的和,最终分别输出三个矩阵。
时间: 2023-10-06 07:04:45 浏览: 127
以下是Python代码实现:
```python
import random
# 随机生成两个3*4的整数矩阵
matrix1 = [[random.randint(1, 10) for j in range(4)] for i in range(3)]
matrix2 = [[random.randint(1, 10) for j in range(4)] for i in range(3)]
# 计算两个矩阵的和
matrix_sum = [[matrix1[i][j] + matrix2[i][j] for j in range(4)] for i in range(3)]
# 分别输出三个矩阵
print("矩阵1:")
for i in range(3):
print(matrix1[i])
print("矩阵2:")
for i in range(3):
print(matrix2[i])
print("矩阵1和矩阵2的和:")
for i in range(3):
print(matrix_sum[i])
```
运行结果示例:
```
矩阵1:
[8, 4, 3, 2]
[10, 7, 10, 4]
[1, 9, 9, 2]
矩阵2:
[10, 6, 8, 1]
[7, 9, 5, 8]
[5, 10, 1, 7]
矩阵1和矩阵2的和:
[18, 10, 11, 3]
[17, 16, 15, 12]
[6, 19, 10, 9]
```
相关问题
python随机生成两个3*4的整数矩阵,计算两个矩阵的和
可以使用random模块中的randint函数随机生成整数,再使用嵌套的列表推导式生成两个矩阵。然后使用嵌套的for循环计算两个矩阵的和,并将结果保存到一个新的矩阵中。代码如下:
```python
import random
# 随机生成两个3*4的整数矩阵
matrix1 = [[random.randint(1, 10) for j in range(4)] for i in range(3)]
matrix2 = [[random.randint(1, 10) for j in range(4)] for i in range(3)]
# 计算两个矩阵的和
result = [[0 for j in range(4)] for i in range(3)]
for i in range(3):
for j in range(4):
result[i][j] = matrix1[i][j] + matrix2[i][j]
# 打印结果
print("矩阵1:")
for row in matrix1:
print(row)
print("矩阵2:")
for row in matrix2:
print(row)
print("两个矩阵的和:")
for row in result:
print(row)
```
运行结果如下:
```
矩阵1:
[1, 9, 9, 3]
[2, 10, 8, 10]
[3, 1, 10, 8]
矩阵2:
[7, 4, 8, 7]
[1, 10, 6, 8]
[9, 9, 6, 1]
两个矩阵的和:
[8, 13, 17, 10]
[3, 20, 14, 18]
[12, 10, 16, 9]
```
用python编写程序,完成3*4矩阵和4*3整数矩阵的乘法,输出结果矩阵
好的,我可以为您提供一份Python代码来完成这个任务:
```python
import numpy as np
# 定义两个矩阵
A = np.array([[1, 2, 3],
[4, 5, 6],
[7, 8, 9],
[10, 11, 12]])
B = np.array([[1, 2, 3, 4],
[5, 6, 7, 8],
[9, 10, 11, 12]])
# 计算矩阵乘积
C = np.dot(A, B)
# 输出结果矩阵
print(C)
```
这个代码使用了Python的NumPy库来完成矩阵乘法,首先定义了两个矩阵A和B,然后使用NumPy的dot函数来计算它们的乘积,最后输出结果矩阵C。
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