使用c语言写出代码
时间: 2023-08-02 17:09:07 浏览: 52
好的,以下是C语言的代码实现:
```c
#include <stdio.h>
#include <string.h>
// 统计字符串 s 与 t 的不同字符个数
int diff_count(char s[], char t[]) {
int len = strlen(s);
int count = 0;
for (int i = 0; i < len; i++) {
if (s[i] != t[i]) {
count++;
}
}
return count;
}
int main() {
int t;
scanf("%d", &t);
char s[9] = "iloveqaq";
while (t--) {
char str[9];
scanf("%s", str);
printf("%d\n", diff_count(s, str));
}
return 0;
}
```
代码思路很简单,先定义一个函数 `diff_count` 来统计两个字符串的不同字符个数,然后在主函数中读入每个字符串,调用 `diff_count` 函数进行统计并输出即可。
相关问题
使用C语言写出贪吃蛇代码
对于一个AI语言模型来说,无法生成可运行的代码。下面给出一个简单的贪吃蛇C语言代码,希望能对你有所帮助。
```c
#include <stdio.h>
#include <stdlib.h>
#include <conio.h>
#include <windows.h>
#define WIDTH 20
#define HEIGHT 20
int x, y, fruitX, fruitY, score;
int tailX[100], tailY[100], nTail;
enum eDirection { STOP = 0, LEFT, RIGHT, UP, DOWN };
enum eDirection dir;
void Setup()
{
dir = STOP;
x = WIDTH / 2;
y = HEIGHT / 2;
fruitX = rand() % WIDTH;
fruitY = rand() % HEIGHT;
score = 0;
}
void Draw()
{
system("cls");
for (int i = 0; i < WIDTH + 2; i++)
printf("#");
printf("\n");
for (int i = 0; i < HEIGHT; i++)
{
for (int j = 0; j < WIDTH; j++)
{
if (j == 0)
printf("#");
if (i == y && j == x)
printf("O");
else if (i == fruitY && j == fruitX)
printf("F");
else
{
int print = 0;
for (int k = 0; k < nTail; k++)
{
if (tailX[k] == j && tailY[k] == i)
{
printf("o");
print = 1;
}
}
if (!print)
printf(" ");
}
if (j == WIDTH - 1)
printf("#");
}
printf("\n");
}
for (int i = 0; i < WIDTH + 2; i++)
printf("#");
printf("\n");
printf("Score: %d\n", score);
}
void Input()
{
if (_kbhit())
{
switch (_getch())
{
case 'a':
dir = LEFT;
break;
case 'd':
dir = RIGHT;
break;
case 'w':
dir = UP;
break;
case 's':
dir = DOWN;
break;
case 'x':
exit(0);
break;
}
}
}
void Logic()
{
int prevX = tailX[0];
int prevY = tailY[0];
int prev2X, prev2Y;
tailX[0] = x;
tailY[0] = y;
for (int i = 1; i < nTail; i++)
{
prev2X = tailX[i];
prev2Y = tailY[i];
tailX[i] = prevX;
tailY[i] = prevY;
prevX = prev2X;
prevY = prev2Y;
}
switch (dir)
{
case LEFT:
x--;
break;
case RIGHT:
x++;
break;
case UP:
y--;
break;
case DOWN:
y++;
break;
default:
break;
}
if (x > WIDTH || x < 0 || y > HEIGHT || y < 0)
exit(0);
for (int i = 0; i < nTail; i++)
if (tailX[i] == x && tailY[i] == y)
exit(0);
if (x == fruitX && y == fruitY)
{
score += 10;
fruitX = rand() % WIDTH;
fruitY = rand() % HEIGHT;
nTail++;
}
}
int main()
{
Setup();
while (1)
{
Draw();
Input();
Logic();
Sleep(10);
}
return 0;
}
```
求二维数组两条对角线的和使用c语言写出代码
以下是求二维数组两条对角线的和的C语言代码:
```
#include <stdio.h>
#define ROWS 3
#define COLS 3
int main()
{
int matrix[ROWS][COLS] = {{1, 2, 3},
{4, 5, 6},
{7, 8, 9}};
int sum_left = 0;
int sum_right = 0;
// 计算左对角线上的元素之和
for (int i = 0; i < ROWS; i++) {
for (int j = 0; j < COLS; j++) {
if (i == j) {
sum_left += matrix[i][j];
}
}
}
// 计算右对角线上的元素之和
for (int i = 0; i < ROWS; i++) {
for (int j = 0; j < COLS; j++) {
if (i == ROWS - j - 1) {
sum_right += matrix[i][j];
}
}
}
printf("左对角线和为:%d\n", sum_left);
printf("右对角线和为:%d\n", sum_right);
return 0;
}
```