different types for formal and
时间: 2023-04-26 10:02:58 浏览: 135
informal writing
正式和非正式写作有不同的类型。在正式写作中,需要使用正式的语言和格式,例如使用完整的句子和正确的标点符号。此外,正式写作通常需要遵循特定的结构和规则,例如使用目录、引用和参考文献。相反,在非正式写作中,可以使用更随意的语言和格式,例如使用缩写、俚语和口语。此外,非正式写作通常更加个人化和情感化,可以包含更多的个人观点和体验。因此,选择适当的写作类型取决于写作的目的和受众。
相关问题
different+types+for+formal+and
不同类型的形式和实际参数是指在函数调用中,形式参数和实际参数的数据类型不匹配的情况。这可能会导致编译器发出警告或错误。
例如,引用中的警告C4024指出,在C语言中,函数gets的形式参数和实际参数的数据类型不匹配。
以下是一个示例,演示了不同类型的形式和实际参数的情况:
```c
#include <stdio.h>
void printNumber(int num) {
printf("The number is: %d\n", num);
}
int main() {
float num = 3.14;
printNumber(num); // 警告:不同类型的形式和实际参数
return 0;
}
```
在上面的示例中,printNumber函数的形式参数是int类型,但在main函数中调用该函数时,传递了一个float类型的实际参数。这导致编译器发出警告,因为形式参数和实际参数的数据类型不匹配。
method Math.min(int,int) is not applicable (actual and formal arguent lists differ in length)method Math.min(long,long) is not applicable (actual and formal argument lists differ in length)method Math.min(float,float) is not applicable(actual and formal a
rgument lists differ in length)method Math.min(double,double) is not applicable (actual and formal argument lists differ in length)
The error message you are seeing indicates that you are trying to call the `Math.min()` method with an incorrect number of arguments.
The `Math.min()` method is overloaded, meaning it has multiple versions that accept different argument types. In this case, there are four versions: `int`, `long`, `float`, and `double`. Each version of the method accepts two arguments of the corresponding type and returns the smaller of the two values.
To fix the error, make sure you are calling the `Math.min()` method with the correct number and type of arguments. For example, if you want to find the minimum of two integers, you should call `Math.min()` with two `int` arguments:
```java
int min = Math.min(5, 10);
```
If you are working with different types of arguments, such as `long`, `float`, or `double`, make sure to provide two arguments of the appropriate type:
```java
long minLong = Math.min(100L, 200L);
float minFloat = Math.min(3.14f, 2.71f);
double minDouble = Math.min(3.14, 2.71);
```
By providing the correct number and type of arguments, you should be able to resolve the error.
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