int i=0; int[] a = {1, 2, 3, 4, 5}; do{System.out.print(a[i++]);} while(i<= a.length);

This code will result in an ArrayIndexOutOfBoundsException because the condition in the do-while loop is checking if i is less than or equal to the length of the array a. However, arrays in Java are zero-indexed, meaning that the last valid index in the array is a.length - 1. Therefore, when i reaches the value of a.length, it will try to access an index that is outside the bounds of the array.

To fix this issue, the condition in the do-while loop should be changed to i < a.length:

int i=0;
int[] a = {1, 2, 3, 4, 5};
do {
System.out.print(a[i]);
i++;
} while(i < a.length);

This will print out all the elements in the array a: 12345.