i=1;while(i<=n) i=5*i;
时间: 2023-12-30 21:06:47 浏览: 20
This code initializes the variable i to 1 and then enters a while loop that continues as long as i is less than or equal to n. Within the loop, i is multiplied by 5, which means that each iteration of the loop will increase i by a factor of 5. The loop will continue until i becomes greater than n.
For example, if n = 100, the loop would execute as follows:
i = 1
i = 5
i = 25
i = 125
At this point, i is greater than n (100), so the loop would exit. The final value of i would be 125.
相关问题
for(m=1;m<n;m++) { i=1; while(i<n) { i=i*2; } }结果是多少
该代码存在语法错误,缺少循环条件的更新语句。应该将代码改为:
for (m=1; m<n; m++) {
i=1;
while (i<n) {
i=i*2;
}
}
此代码中,外层循环执行n-1次,内层循环执行log2(n)次。因此,总的执行次数为(n-1) * log2(n)。
for(m=1;m<n;m++) { i=1; while(i<n) { i=i*2; } }
This code is incomplete as there is no closing bracket for the outer for loop. Without knowing the value of n, it is difficult to determine the purpose of this code. However, it appears to be a nested loop structure where the inner while loop iteratively doubles the value of i until it reaches or exceeds the value of n. The outer for loop likely controls the number of times the inner loop executes.