手术排程问题:最大化手术室黄金时间利用率的仿真模型python具体代码
时间: 2023-10-08 12:05:50 浏览: 51
手术排程问题是一个经典的组合优化问题,可以用多种算法求解。以下是一个基于禁忌搜索算法的手术排程的仿真模型的Python代码示例:
```python
import random
# 手术室数量
num_rooms = 5
# 手术室工作时间段
work_hours = (8, 18)
# 每个手术的时长
op_time = [random.randint(1, 4) for i in range(20)]
# 定义禁忌搜索参数
tabu_size = 10
max_iter = 100
# 初始化排程
schedule = [[0 for i in range(work_hours[1] - work_hours[0])] for j in range(num_rooms)]
# 计算黄金时间利用率
def calc_golden_time_util(schedule):
total_golden_time = num_rooms * (work_hours[1] - work_hours[0])
used_golden_time = sum([sum([1 for t in row if t > 0]) for row in schedule])
return used_golden_time / total_golden_time
# 定义禁忌搜索函数
def tabu_search():
# 初始化禁忌表
tabu_list = []
# 初始化当前最优解
best_schedule = schedule
best_util = calc_golden_time_util(best_schedule)
# 迭代搜索
for i in range(max_iter):
# 生成邻居解集
neighbors = []
for room in range(num_rooms):
for time in range(work_hours[1] - work_hours[0] - op_time[i]):
neighbor = [row[:] for row in schedule]
for t in range(op_time[i]):
neighbor[room][time+t] = i+1
neighbors.append((neighbor, room, time))
# 选择最好的非禁忌解
best_neighbor = None
best_neighbor_util = 0
for neighbor in neighbors:
neighbor_util = calc_golden_time_util(neighbor[0])
if (neighbor not in tabu_list) and (neighbor_util > best_neighbor_util):
best_neighbor = neighbor
best_neighbor_util = neighbor_util
# 更新当前解
if best_neighbor_util > best_util:
best_schedule = best_neighbor[0]
best_util = best_neighbor_util
# 更新禁忌表
tabu_list.append(best_neighbor)
if len(tabu_list) > tabu_size:
tabu_list.pop(0)
return best_schedule
# 输出最优解和黄金时间利用率
best_schedule = tabu_search()
best_util = calc_golden_time_util(best_schedule)
print("Best schedule:")
for i in range(len(best_schedule)):
print("Room {}: {}".format(i+1, best_schedule[i]))
print("Golden time utilization: {:.2%}".format(best_util))
```
该代码实现了一个简单的手术排程问题的仿真模型,使用了禁忌搜索算法进行求解。在模型中,我们首先定义了手术室数量和工作时间段,并随机生成了每个手术的时长。然后,我们初始化了排程和禁忌表,并迭代搜索邻居解集,选择最好的非禁忌解进行更新。最后输出了最优解和黄金时间利用率。需要注意的是,该代码只是一个简单的示例,实际应用中需要根据具体问题进行修改和优化。
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