写出两位全加器的testbench代码
时间: 2023-09-22 21:14:50 浏览: 57
很高兴为您解答问题。以下是两位全加器的testbench代码:
`module full_adder_tb;
reg [1:0] a, b, cin;
wire [1:0] sum;
wire cout;
full_adder fa(
.a(a),
.b(b),
.cin(cin),
.sum(sum),
.cout(cout)
);
initial
begin
a = 0; b = 0; cin = 0;
#10 a = 0; b = 1; cin = 0;
#10 a = 1; b = 0; cin = 0;
#10 a = 1; b = 1; cin = 0;
#10 a = 0; b = 0; cin = 1;
#10 a = 0; b = 1; cin = 1;
#10 a = 1; b = 0; cin = 1;
#10 a = 1; b = 1; cin = 1;
end
endmodule`
希望能为您提供帮助!
相关问题
16位全加器的testbench代码
以下是一个16位全加器的testbench代码,使用Verilog语言编写:
```
module full_adder_tb;
// Inputs
reg [15:0] a, b, cin;
// Outputs
wire [15:0] sum, cout;
// Instantiate the DUT
full_adder dut (
.a(a),
.b(b),
.cin(cin),
.sum(sum),
.cout(cout)
);
// Define clock period
parameter PERIOD = 10;
// Clock signal
reg clk = 0;
always #PERIOD/2 clk = ~clk;
// Test case 1
initial begin
a = 16'h0000;
b = 16'h0000;
cin = 1;
#PERIOD $display("a = %h, b = %h, cin = %h, sum = %h, cout = %h", a, b, cin, sum, cout);
end
// Test case 2
initial begin
a = 16'hFFFF;
b = 16'hFFFF;
cin = 0;
#PERIOD $display("a = %h, b = %h, cin = %h, sum = %h, cout = %h", a, b, cin, sum, cout);
end
// Test case 3
initial begin
a = 16'hF0F0;
b = 16'h0F0F;
cin = 0;
#PERIOD $display("a = %h, b = %h, cin = %h, sum = %h, cout = %h", a, b, cin, sum, cout);
end
// Test case 4
initial begin
a = 16'h1234;
b = 16'h5678;
cin = 1;
#PERIOD $display("a = %h, b = %h, cin = %h, sum = %h, cout = %h", a, b, cin, sum, cout);
end
endmodule
```
在上面的代码中,我们首先定义了输入信号a、b和cin,以及输出信号sum和cout。然后我们实例化了我们要测试的模块full_adder,并将输入信号和输出信号连接到该模块中。接下来,我们定义了时钟信号clk,并使用always块来生成一个周期为PERIOD的时钟信号。最后,我们定义了四个测试用例,每个测试用例对应于一组不同的输入信号,并在每个测试用例中显示输入和输出信号的值。当我们运行这个testbench时,它将自动运行这四个测试用例,并在仿真窗口中显示每个测试用例的结果。
ModelSim实现16位全加器和16位全加器的testbench
以下是16位全加器的Verilog代码:
```
module full_adder(
input wire a,
input wire b,
input wire cin,
output reg sum,
output reg cout
);
always @(*) begin
sum = a ^ b ^ cin;
cout = (a & b) | (a & cin) | (b & cin);
end
endmodule
module sixteen_bit_adder(
input wire [15:0] a,
input wire [15:0] b,
input wire cin,
output reg [15:0] sum,
output reg cout
);
reg [15:0] s;
reg c;
always @(*) begin
s[0] = cin;
for (int i = 0; i < 15; i = i + 1) begin
full_adder fa(
.a(a[i]),
.b(b[i]),
.cin(s[i]),
.sum(s[i+1]),
.cout(c)
);
end
sum = s;
cout = c;
end
endmodule
```
以下是16位全加器的testbench代码:
```
module sixteen_bit_adder_tb;
// Inputs
reg [15:0] a;
reg [15:0] b;
reg cin;
// Outputs
wire [15:0] sum;
wire cout;
// Instantiate the Unit Under Test (UUT)
sixteen_bit_adder uut (
.a(a),
.b(b),
.cin(cin),
.sum(sum),
.cout(cout)
);
initial begin
// Initialize Inputs
a = 16'hFFFF;
b = 16'h0001;
cin = 0;
// Wait 100 ns for global reset to finish
#100;
// Add stimulus here
// ...
// Add clock here
// ...
// Check the outputs
if (sum !== 16'h0000 || cout !== 1'b0) begin
$display("Test failed!");
end else begin
$display("Test passed!");
end
// Add cleanup code here
// ...
// Finish the simulation
$finish;
end
endmodule
```
请注意,这只是一个简单的测试台,您需要根据您的需求添加适当的输入刺激和时钟。