写一段代码，要求顺序存储实现入栈出栈，把中缀表达式转换为后缀表达式的算法

好的，以下是符合您需求的C++代码：

#include <iostream>
#include <stack>
#include <string>

using namespace std;

int precedence(char op) {

if (op == '+' || op == '-') {
return 1;
}

if (op == '*' || op == '/') {
return 2;
}

return 0;
}

string infixToPostfix(string infix) {

stack<char> s;
string postfix = "";

for (int i = 0; i < infix.length(); i++) {

if (infix[i] >= '0' && infix[i] <= '9') {
postfix += infix[i];
}

else if (infix[i] == '(') {
s.push('(');
}

else if (infix[i] == ')') {

while (!s.empty() && s.top() != '(') {
postfix += s.top();
s.pop();
}

if (!s.empty() && s.top() != '(') {
return "Invalid Expression";
}
else {
s.pop();
}
}

else {

while (!s.empty() && precedence(infix[i]) <= precedence(s.top())) {
postfix += s.top();
s.pop();
}

s.push(infix[i]);
}
}

while (!s.empty()) {
postfix += s.top();
s.pop();
}

return postfix;
}

int main() {

string infix = "2+3*4";
cout << "Infix Expression: " << infix << endl;

string postfix = infixToPostfix(infix);
cout << "Postfix Expression: " << postfix << endl;

return 0;
}

对于入栈出栈的实现，您可以使用一个数组来模拟栈，以下是示例代码：

#define MAX_SIZE 1000

class Stack {

private:
int top;
int arr[MAX_SIZE];

public:
Stack() {
top = -1;
}

bool push(int x) {
if (top >= (MAX_SIZE - 1)) {
cout << "Stack Overflow" << endl;
return false;
}
else {
arr[++top] = x;
return true;
}
}

int pop() {
if (top < 0) {
cout << "Stack Underflow" << endl;
return 0;
}
else {
int x = arr[top--];
return x;
}
}

int peek() {
if (top < 0) {
cout << "Stack is Empty" << endl;
return 0;
}
else {
int x = arr[top];
return x;
}
}

bool isEmpty() {
return (top < 0);
}
};

int main() {

Stack s;

s.push(10);
s.push(20);
s.push(30);

cout << s.pop() << endl;
cout << s.peek() << endl;

return 0;
}

希望对您有所帮助！