用c语言写一个三子棋代码

好的，以下是一个简单的用C语言实现三子棋的代码，供参考：

#include <stdio.h>
#include <stdlib.h>

// 定义棋盘大小
#define ROWS 3
#define COLS 3

// 定义棋子类型
#define EMPTY ' '
#define PLAYER 'X'
#define COMPUTER 'O'

// 初始化棋盘
void initializeBoard(char board[ROWS][COLS]) {
    int i, j;
    for (i = 0; i < ROWS; i++) {
        for (j = 0; j < COLS; j++) {
            board[i][j] = EMPTY;
        }
    }
}

// 打印棋盘
void printBoard(char board[ROWS][COLS]) {
    int i, j;
    printf("\n");
    for (i = 0; i < ROWS; i++) {
        printf(" %c | %c | %c ", board[i][0], board[i][1], board[i][2]);
        if (i != ROWS - 1) {
            printf("\n---|---|---\n");
        }
    }
    printf("\n");
}

// 获取玩家输入
void getPlayerMove(char board[ROWS][COLS], int *row, int *col) {
    printf("请输入您下棋的位置（行和列），以逗号分隔：");
    scanf("%d,%d", row, col);
    while (board[*row-1][*col-1] != EMPTY) {
        printf("该位置已有棋子，请重新输入：");
        scanf("%d,%d", row, col);
    }
}

// 判断游戏是否结束
int isGameOver(char board[ROWS][COLS], char player) {
    int i, j, isTie = 1;
    // 判断行
    for (i = 0; i < ROWS; i++) {
        if (board[i][0] == player && board[i][1] == player && board[i][2] == player) {
            return 1;
        }
        if (board[i][0] == EMPTY || board[i][1] == EMPTY || board[i][2] == EMPTY) {
            isTie = 0;
        }
    }
    // 判断列
    for (j = 0; j < COLS; j++) {
        if (board[0][j] == player && board[1][j] == player && board[2][j] == player) {
            return 1;
        }
    }
    // 判断对角线
    if (board[0][0] == player && board[1][1] == player && board[2][2] == player) {
        return 1;
    }
    if (board[0][2] == player && board[1][1] == player && board[2][0] == player) {
        return 1;
    }
    // 判断是否平局
    if (isTie == 1) {
        return 2;
    }
    return 0;
}

// 计算电脑下棋的位置
void getComputerMove(char board[ROWS][COLS], int *row, int *col) {
    int i, j, count = 0, maxCount = 0, maxRow = 0, maxCol = 0;
    // 遍历棋盘
    for (i = 0