dp[i]+=dp[i-j];

This statement is incomplete and lacks context, but it appears to be part of a dynamic programming algorithm. Generally, in dynamic programming, dp[i] represents the value of the optimal solution to a subproblem at index i, and dp[i-j] represents the value of the optimal solution to a subproblem at index i-j. Without more information about the specific problem and algorithm, it is difficult to provide a more detailed explanation.

相关问题

#include<stdio.h> int map[11][11], dp[11][11];int main(){int n, i, j, num=0, res=0;scanf("%d", &n);for (i = 1; i <= n; i++)for (j = 1; j <= n; j++){map[i][j] = 0;dp[i][j] = 0;}while (map[i][j] || i || j){scanf("%d%d", &i, &j);scanf("%d", &map[i][j]);dp[i][j] = map[i][j];}for (int i = 2; i <= n; i++){dp[1][i] += dp[1][i - 1];dp[i][1] += dp[i - 1][1];}for (int i = 2; i <= n; i++)for (int j = 2; j <= n; j++)if (dp[i - 1][j] != 0 || dp[i][j - 1] != 0)if (dp[i - 1][j] > dp[i][j - 1])dp[i][j] += dp[i - 1][j];else dp[i][j] += dp[i][j - 1];num += dp[n][n];res = num;for (int i = 1; i <= n; i++){for (int j = 1; j <= n; j++){if (dp[i][j] == num){if (map[i][j] + dp[i - 1][j] == num || map[i][j] + dp[i][j - 1] == num){num -= map[i][j];map[i][j] = 0;i = 1;j = 0;if (num == 0)break;}}}if (num == 0)break;}for (int i = 2; i <= n; i++)for (int j = 2; j <= n; j++)if (map[i - 1][j] != 0 || map[i][j - 1] != 0)if (map[i - 1][j] > map[i][j - 1])map[i][j] += map[i - 1][j];else map[i][j] += map[i][j - 1];res += map[n][n];printf("%d", res);return 0;}格式化这段代码

#include<stdio.h>

int map[11][11], dp[11][11];

int main(){
int n, i, j, num=0, res=0;
scanf("%d", &n);
for (i = 1; i <= n; i++){
for (j = 1; j <= n; j++){
map[i][j] = 0;
dp[i][j] = 0;
}
}
while (map[i][j] || i || j){
scanf("%d%d", &i, &j);
scanf("%d", &map[i][j]);
dp[i][j] = map[i][j];
}
for (int i = 2; i <= n; i++){
dp[1][i] += dp[1][i - 1];
dp[i][1] += dp[i - 1][1];
}
for (int i = 2; i <= n; i++){
for (int j = 2; j <= n; j++){
if (dp[i - 1][j] != 0 || dp[i][j - 1] != 0){
if (dp[i - 1][j] > dp[i][j - 1]){
dp[i][j] += dp[i - 1][j];
}
else{
dp[i][j] += dp[i][j - 1];
}
}
}
}
num += dp[n][n];
res = num;
for (int i = 1; i <= n; i++){
for (int j = 1; j <= n; j++){
if (dp[i][j] == num){
if (map[i][j] + dp[i - 1][j] == num || map[i][j] + dp[i][j - 1] == num){
num -= map[i][j];
map[i][j] = 0;
i = 1;
j = 0;
if (num == 0){
break;
}
}
}
}
if (num == 0){
break;
}
}
for (int i = 2; i <= n; i++){
for (int j = 2; j <= n; j++){
if (map[i - 1][j] != 0 || map[i][j - 1] != 0){
if (map[i - 1][j] > map[i][j - 1]){
map[i][j] += map[i - 1][j];
}
else{
map[i][j] += map[i][j - 1];
}
}
}
}
res += map[n][n];
printf("%d", res);
return 0;
}

#include<stdio.h> int map[11][11], dp[11][11]; int main() { int n, i, j, num = 0, res = 0; scanf("%d", &n); for (i = 1; i <= n; i++) for (j = 1; j <= n; j++) { map[i][j] = 0; dp[i][j] = 0; } while (map[i][j] || i || j) { scanf("%d%d", &i, &j); scanf("%d", &map[i][j]); dp[i][j] = map[i][j]; } for (int i = 2; i <= n; i++) { dp[1][i] += dp[1][i - 1]; dp[i][1] += dp[i - 1][1]; } for (int i = 2; i <= n; i++) for (int j = 2; j <= n; j++) if (dp[i - 1][j] != 0 || dp[i][j - 1] != 0) if (dp[i - 1][j] > dp[i][j - 1]) dp[i][j] += dp[i - 1][j]; else dp[i][j] += dp[i][j - 1]; num += dp[n][n]; res = num; for (int i = 1; i <= n; i++) { for (int j = 1; j <= n; j++) { if (dp[i][j] == num) { if (map[i][j] + dp[i - 1][j] == num || map[i][j] + dp[i][j - 1] == num) { num -= map[i][j]; map[i][j] = 0; i = 1; j = 0; if (num == 0) break; } } } if (num == 0) break; } for (int i = 2; i <= n; i++) for (int j = 2; j <= n; j++) if (map[i - 1][j] != 0 || map[i][j - 1] != 0) if (map[i - 1][j] > map[i][j - 1]) map[i][j] += map[i - 1][j]; else map[i][j] += map[i][j - 1]; res += map[n][n]; printf("%d", res); return 0; }优化

可以将一些重复的代码封装成函数，以提高代码可读性和可维护性。例如，可以将计算最大价值和删除路径上某个点的操作封装成函数。

此外，可以使用更具有表达性的变量名，以便于理解代码含义。

下面是一个可能的优化版本：

#include <stdio.h>

#define MAX_N 11

int map[MAX_N][MAX_N], dp[MAX_N][MAX_N];

int read_input(int n) {
    int i, j;
    while (scanf("%d%d", &i, &j) == 2) {
        scanf("%d", &map[i][j]);
        dp[i][j] = map[i][j];
    }
    return 0;
}

int compute_max_value(int n) {
    int i, j;
    for (i = 2; i <= n; i++) {
        dp[1][i] += dp[1][i - 1];
        dp[i][1] += dp[i - 1][1];
    }
    for (i = 2; i <= n; i++) {
        for (j = 2; j <= n; j++) {
            if (dp[i - 1][j] != 0 || dp[i][j - 1] != 0) {
                dp[i][j] += dp[i - 1][j] > dp[i][j - 1] ? dp[i - 1][j] : dp[i][j - 1];
            }
        }
    }
    return dp[n][n];
}

int delete_path(int n, int max_value) {
    int i, j;
    int current_value = max_value;
    while (current_value > 0) {
        for (i = 1; i <= n; i++) {
            for (j = 1; j <= n; j++) {
                if (dp[i][j] == current_value) {
                    if (map[i][j] + dp[i - 1][j] == current_value || map[i][j] + dp[i][j - 1] == current_value) {
                        current_value -= map[i][j];
                        map[i][j] = 0;
                        i = 1;
                        j = 0;
                        if (current_value == 0) {
                            return 0;
                        }
                    }
                }
            }
        }
        current_value--;
    }
    return 0;
}

int compute_max_path(int n) {
    int i, j;
    for (i = 2; i <= n; i++) {
        for (j = 2; j <= n; j++) {
            if (map[i - 1][j] != 0 || map[i][j - 1] != 0) {
                map[i][j] += map[i - 1][j] > map[i][j - 1] ? map[i - 1][j] : map[i][j - 1];
            }
        }
    }
    return map[n][n];
}

int main() {
    int n, max_value, max_path;
    scanf("%d", &n);
    read_input(n);
    max_value = compute_max_value(n);
    delete_path(n, max_value);
    max_path = compute_max_path(n);
    printf("%d", max_value + max_path);
    return 0;
}