代码dp[i][j] = dp[i+1][j-1] + dp[i+1][j] + dp[i+1][j+1] 报错了,报错信息为IndexError: list index out of range
时间: 2023-09-19 18:10:00 浏览: 38
非常抱歉,之前的代码中没有考虑到竖直对称线的左侧,因此在计算状态转移方程时会出现数组下标越界的情况。在状态转移方程中,我们需要考虑到当前小正六边形的左侧、正下方和右侧三个小正六边形,而左侧的小正六边形的列下标为 $N+1-j$。
以下是修改后的 Python 代码实现:
```python
N = int(input())
# 初始化状态
dp = [[0] * (2*N+1) for _ in range(N+1)]
for j in range(N+1, 2*N+1):
dp[N][j] = 1
# 计算状态转移方程
for i in range(N-1, -1, -1):
for j in range(i+1, 2*N-i):
if j <= N:
dp[i][j] = dp[i+1][j-1] + dp[i+1][j] + dp[i+1][j+1]
else:
dp[i][j] = dp[i+1][2*N-j+1] + dp[i+1][2*N-j] + dp[i+1][2*N-j-1]
# 计算最终答案
if N % 2 == 0:
print(dp[0][N+1] * 2)
else:
print(dp[0][N+1])
```
再次感谢您的指正,希望我的回答能够帮助您解决问题!
相关问题
dp[i]+=dp[i-j];
This statement is incomplete and lacks context, but it appears to be part of a dynamic programming algorithm. Generally, in dynamic programming, dp[i] represents the value of the optimal solution to a subproblem at index i, and dp[i-j] represents the value of the optimal solution to a subproblem at index i-j. Without more information about the specific problem and algorithm, it is difficult to provide a more detailed explanation.
#include<stdio.h> int map[11][11], dp[11][11];int main(){int n, i, j, num=0, res=0;scanf("%d", &n);for (i = 1; i <= n; i++)for (j = 1; j <= n; j++){map[i][j] = 0;dp[i][j] = 0;}while (map[i][j] || i || j){scanf("%d%d", &i, &j);scanf("%d", &map[i][j]);dp[i][j] = map[i][j];}for (int i = 2; i <= n; i++){dp[1][i] += dp[1][i - 1];dp[i][1] += dp[i - 1][1];}for (int i = 2; i <= n; i++)for (int j = 2; j <= n; j++)if (dp[i - 1][j] != 0 || dp[i][j - 1] != 0)if (dp[i - 1][j] > dp[i][j - 1])dp[i][j] += dp[i - 1][j];else dp[i][j] += dp[i][j - 1];num += dp[n][n];res = num;for (int i = 1; i <= n; i++){for (int j = 1; j <= n; j++){if (dp[i][j] == num){if (map[i][j] + dp[i - 1][j] == num || map[i][j] + dp[i][j - 1] == num){num -= map[i][j];map[i][j] = 0;i = 1;j = 0;if (num == 0)break;}}}if (num == 0)break;}for (int i = 2; i <= n; i++)for (int j = 2; j <= n; j++)if (map[i - 1][j] != 0 || map[i][j - 1] != 0)if (map[i - 1][j] > map[i][j - 1])map[i][j] += map[i - 1][j];else map[i][j] += map[i][j - 1];res += map[n][n];printf("%d", res);return 0;}格式化这段代码
#include<stdio.h>
int map[11][11], dp[11][11];
int main(){
int n, i, j, num=0, res=0;
scanf("%d", &n);
for (i = 1; i <= n; i++){
for (j = 1; j <= n; j++){
map[i][j] = 0;
dp[i][j] = 0;
}
}
while (map[i][j] || i || j){
scanf("%d%d", &i, &j);
scanf("%d", &map[i][j]);
dp[i][j] = map[i][j];
}
for (int i = 2; i <= n; i++){
dp[1][i] += dp[1][i - 1];
dp[i][1] += dp[i - 1][1];
}
for (int i = 2; i <= n; i++){
for (int j = 2; j <= n; j++){
if (dp[i - 1][j] != 0 || dp[i][j - 1] != 0){
if (dp[i - 1][j] > dp[i][j - 1]){
dp[i][j] += dp[i - 1][j];
}
else{
dp[i][j] += dp[i][j - 1];
}
}
}
}
num += dp[n][n];
res = num;
for (int i = 1; i <= n; i++){
for (int j = 1; j <= n; j++){
if (dp[i][j] == num){
if (map[i][j] + dp[i - 1][j] == num || map[i][j] + dp[i][j - 1] == num){
num -= map[i][j];
map[i][j] = 0;
i = 1;
j = 0;
if (num == 0){
break;
}
}
}
}
if (num == 0){
break;
}
}
for (int i = 2; i <= n; i++){
for (int j = 2; j <= n; j++){
if (map[i - 1][j] != 0 || map[i][j - 1] != 0){
if (map[i - 1][j] > map[i][j - 1]){
map[i][j] += map[i - 1][j];
}
else{
map[i][j] += map[i][j - 1];
}
}
}
}
res += map[n][n];
printf("%d", res);
return 0;
}