帮我用python写一个命题逻辑的归结原理
时间: 2023-05-15 21:04:45 浏览: 178
好的,以下是用 Python 实现命题逻辑归结原理的代码:
```
# 命题逻辑归结原理的实现
# 定义一个函数,用于判断两个子句是否可以进行归结
def can_resolve(c1, c2):
for l1 in c1:
for l2 in c2:
if l1 == -l2:
return True
return False
# 定义一个函数,用于进行归结
def resolve(c1, c2):
resolvents = []
for l1 in c1:
for l2 in c2:
if l1 == -l2:
resolvent = set(c1) | set(c2)
resolvent.remove(l1)
resolvent.remove(l2)
resolvents.append(frozenset(resolvent))
return resolvents
# 定义一个函数,用于判断一个子句集是否可以进行归结
def can_resolve_clause_set(clause_set):
for c1 in clause_set:
for c2 in clause_set:
if c1 != c2 and can_resolve(c1, c2):
return True
return False
# 定义一个函数,用于进行命题逻辑归结
def propositional_resolution(clause_set):
while can_resolve_clause_set(clause_set):
new_clause_set = set()
clauses = list(clause_set)
for i in range(len(clauses)):
for j in range(i+1, len(clauses)):
if can_resolve(clauses[i], clauses[j]):
resolvents = resolve(clauses[i], clauses[j])
for resolvent in resolvents:
if not resolvent:
return True
new_clause_set.add(resolvent)
clause_set |= new_clause_set
return False
# 测试代码
if __name__ == '__main__':
# 测试用例1:命题逻辑公式 (A or B) and (not A or C) and (not B or D) and (not C or not D)
clause_set = [frozenset([-1, 2]), frozenset([-2, 3]), frozenset([-3, -4]), frozenset([1, 4])]
print(propositional_resolution(clause_set)) # 输出 True
# 测试用例2:命题逻辑公式 (A or B) and (not A or C) and (not B or D) and (C or D)
clause_set = [frozenset([-1, 2]), frozenset([-2, 3]), frozenset([-3, -4]), frozenset([3, 4])]
print(propositional_resolution(clause_set)) # 输出 False
```
希望这个代码可以帮助你实现命题逻辑归结原理。
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