java 递归解析json_Java递归解析任意层的Json数据，获取所有的key和value，

好的，这个问题需要用到JSON解析库和递归算法。我推荐使用Jackson作为JSON解析库，以下是一个Java递归解析任意层的JSON数据的示例代码：

import com.fasterxml.jackson.databind.JsonNode;
import com.fasterxml.jackson.databind.ObjectMapper;

import java.util.Iterator;

public class JsonParser {
    public static void parseJson(String jsonStr) throws Exception {
        ObjectMapper mapper = new ObjectMapper();
        JsonNode rootNode = mapper.readTree(jsonStr);
        parseNode(rootNode, "");
    }

    private static void parseNode(JsonNode node, String prefix) {
        if (node.isObject()) {
            Iterator<String> fieldNames = node.fieldNames();
            while (fieldNames.hasNext()) {
                String fieldName = fieldNames.next();
                JsonNode childNode = node.get(fieldName);
                String newPrefix = prefix.isEmpty() ? fieldName : prefix + "." + fieldName;
                parseNode(childNode, newPrefix);
            }
        } else if (node.isArray()) {
            for (int i = 0; i < node.size(); i++) {
                JsonNode childNode = node.get(i);
                String newPrefix = prefix.isEmpty() ? "[" + i + "]" : prefix + "[" + i + "]";
                parseNode(childNode, newPrefix);
            }
        } else {
            System.out.println(prefix + " = " + node.asText());
        }
    }
}

调用示例：

String jsonStr = "{\"name\":\"John Smith\",\"age\":30,\"address\":{\"street\":\"123 Main St\",\"city\":\"New York\"},\"phoneNumbers\":[{\"type\":\"home\",\"number\":\"555-555-1234\"},{\"type\":\"work\",\"number\":\"555-555-5678\"}]}";
JsonParser.parseJson(jsonStr);

输出结果：

name = John Smith
age = 30
address.street = 123 Main St
address.city = New York
phoneNumbers[0].type = home
phoneNumbers[0].number = 555-555-1234
phoneNumbers[1].type = work
phoneNumbers[1].number = 555-555-5678