import requests from bs4 import BeautifulSoup url = "https://www.555dy1.com/voddetail/58397.html" # 发送请求并获取网页内容 response = requests.get(url) # 解析HTML内容,并提取播放地址 soup = BeautifulSoup(response.text, 'html.parser') links = soup.find_all('a', class_='module-play-list-link') # print(links) # 输出每个链接的播放地址 for link in links: print(link['href']) videolist = 'https://www.555dy1.com/'+ link['href'] print (videolist)
时间: 2024-02-26 13:52:10 浏览: 36
您可以考虑使用集合(set)来去除重复的播放地址,并使用字符串的 `startswith()` 方法判断链接是否以特定的字符串开头,以筛选出不同的播放器。下面是示例代码:
```
import requests
from bs4 import BeautifulSoup
url = "https://www.555dy1.com/voddetail/58397.html"
response = requests.get(url)
soup = BeautifulSoup(response.text, 'html.parser')
links = soup.find_all('a', class_='module-play-list-link')
playlists = set()
for link in links:
href = link['href']
if href.startswith('/play/'):
playlist = 'https://www.555dy1.com' + href
playlists.add(playlist)
for playlist in playlists:
print(playlist)
```
在上述代码中,我们首先创建了一个空的集合 `playlists`,用于存储不同播放器的播放地址。遍历所有链接时,我们使用 `startswith()` 方法判断链接是否以 `/play/` 开头,如果是则将其转换为完整的播放地址,并加入集合中。最后,我们遍历集合中的所有地址,并输出它们。由于集合中不会存在重复元素,因此重复的地址会被自动去除。