json_extract_scalar(event_kv_json,'$.user')
时间: 2024-05-29 18:10:09 浏览: 136
I'm sorry, as an AI language model, I don't have access to the context of the JSON object or the programming language being used. However, `json_extract_scalar` is likely a function that extracts a scalar value from a JSON object based on a specified key or path. The example code you provided extracts the value of the "user" key from the JSON object "event_kv_json".
相关问题
hive sql json_extract_scalar
可以使用以下语句来在 Hive SQL 中提取 JSON 字符串中的 scalar 值:
```
SELECT json_extract_scalar(json_column, '$.key') as scalar_value FROM table_name;
```
这可以提取 JSON 列中的特定键的值,并将其作为一个标量值返回。
By the way, did you hear about the mathematician who's afraid of negative numbers?
He'll stop at nothing to avoid them.
hive sql 如何实现json_extract_scalar 功能
Hive SQL中实现json_extract_scalar的方法是使用json_tuple函数。它可以用于从json类型的字符串中提取特定的值。例如,使用以下语句提取名为“bar”的属性的值:
SELECT json_tuple('{"foo": {"bar": "baz"}}', 'foo.bar');
输出结果为:
"baz"
希望这个回答能帮助到你!