#include<iostream> using namespace std; int t1(int a) { return a + 2; } int t2(int b) { return b + 3; } int q(int(*p)()) { return p(); } int main() { int q(t1(4)); int q(t2(5)); return 0; }这个函数为什么不能正确输出
时间: 2023-12-12 22:04:07 浏览: 45
这段代码中存在一个语法错误,两个函数的调用方式不正确。在main函数中,变量q被定义了两次,这会导致编译器报错。同时,q函数的参数应该是函数指针类型,而不是函数调用,因此需要修改为以下代码:
```
#include<iostream>
using namespace std;
int t1(int a) {
return a + 2;
}
int t2(int b) {
return b + 3;
}
int q(int(*p)()) {
return p();
}
int main() {
int result1 = q(t1);
int result2 = q(t2);
cout << result1 << endl;
cout << result2 << endl;
return 0;
}
```
这样就可以正确输出结果了。
相关问题
#include <iostream> #include <string> using namespace std; template <class T> T SumArray(T* T1,T * T2) { string operator+(string& s1, string &s2) { return s1+s2; } for (T* i = T1; i <= T2; i++) { T S; S
It looks like the code is incomplete and contains errors. The line `string operator+(string& s1, string &s2)` cannot be inside the `SumArray` function. It should be declared outside the function as a global function. Additionally, the code ends abruptly with the variable `S` not being used or returned.
Here's an updated version with those issues fixed:
```
#include <iostream>
#include <string>
using namespace std;
string operator+(string& s1, string &s2) {
return s1 + s2;
}
template <class T>
T SumArray(T* T1, T* T2) {
T sum = 0;
for (T* i = T1; i <= T2; i++) {
sum += *i;
}
return sum;
}
int main() {
int arr1[] = { 1, 2, 3, 4, 5 };
float arr2[] = { 1.1, 2.2, 3.3, 4.4, 5.5 };
string arr3[] = { "hello", "world", "!" };
cout << "Sum of arr1: " << SumArray(arr1, arr1 + 4) << endl;
cout << "Sum of arr2: " << SumArray(arr2, arr2 + 4) << endl;
cout << "Concatenation of arr3: " << SumArray(arr3, arr3 + 2) << endl;
return 0;
}
```
This code defines a global function `operator+` for concatenating two strings, and a template function `SumArray` that takes two pointers and returns the sum of the values between them. It can handle arrays of integers, floats, and strings. The main function demonstrates how to use the `SumArray` function with different types of arrays.
请设计时间类TIME,实现时间的输入、输出和比较。 #include <iostream> #include <iomanip> using namespace std; /* 你提交的代码将被嵌在这里 */ int main() { TIME a, b; cin >> a >> b; if (a > b) { cout << "Yes\n"; } else { cout << "No\n"; } return 0; }
好的,以下是一个简单的 TIME 类的实现,包括输入、输出和比较功能:
```C++
#include <iostream>
#include <iomanip>
using namespace std;
class TIME {
public:
TIME() : hour(0), minute(0), second(0) {}
TIME(int h, int m, int s) : hour(h), minute(m), second(s) {}
friend istream& operator>> (istream& in, TIME& t);
friend ostream& operator<< (ostream& out, const TIME& t);
friend bool operator> (const TIME& t1, const TIME& t2);
private:
int hour, minute, second;
};
istream& operator>> (istream& in, TIME& t) {
in >> t.hour >> t.minute >> t.second;
return in;
}
ostream& operator<< (ostream& out, const TIME& t) {
out << setw(2) << setfill('0') << t.hour << ":"
<< setw(2) << setfill('0') << t.minute << ":"
<< setw(2) << setfill('0') << t.second;
return out;
}
bool operator> (const TIME& t1, const TIME& t2) {
if (t1.hour > t2.hour) {
return true;
} else if (t1.hour == t2.hour && t1.minute > t2.minute) {
return true;
} else if (t1.hour == t2.hour && t1.minute == t2.minute && t1.second > t2.second) {
return true;
} else {
return false;
}
}
int main() {
TIME a, b;
cin >> a >> b;
if (a > b) {
cout << "Yes\n";
} else {
cout << "No\n";
}
return 0;
}
```
在这个实现中,我们定义了一个 TIME 类,其中包括小时、分钟和秒三个成员变量。我们还定义了三个函数:
- `operator>>` 用于从输入流中读取时间值;
- `operator<<` 用于将时间值输出到输出流中;
- `operator>` 用于比较两个时间值的大小。
在主函数中,我们创建了两个 TIME 类型的对象 a 和 b,并从标准输入中读取它们的值。然后,我们使用 `operator>` 比较 a 和 b 的大小,并输出结果。
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